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The chemical process in the production of steel from haematite ore involve:     [JEE 2000 Qualifying]
  • a)
    Reduction
  • b)
    Oxidation
  • c)
    Reduction followed by oxidation
  • d)
    Oxidation follwed by reduction
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The chemical process in the production of steel from haematite ore inv...
The correct answer is d.
Firstly, carbon which is added along which crushed haematite ore is oxidised to CO(andCO2)and second the produced CO acts as chief reducing agent for the reduction of haematite to steel.
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The chemical process in the production of steel from haematite ore inv...
Reduction followed by Oxidation in the Production of Steel from Haematite Ore

Reduction:
- Haematite ore (Fe2O3) is first reduced to iron in a blast furnace.
- Carbon monoxide (CO) is used as a reducing agent to remove oxygen from the iron oxide.
- The chemical equation for the reduction process is: Fe2O3 + 3CO → 2Fe + 3CO2.
- This reduction process converts the iron oxide into iron.

Oxidation:
- The iron obtained from the reduction step is impure and needs to be further processed to remove impurities.
- The impure iron is placed in a furnace along with oxygen to oxidize the impurities.
- The chemical equation for the oxidation process is: 2Fe + O2 → 2FeO.
- This oxidation step helps in removing impurities like carbon, silicon, and phosphorus from the iron.
- The final product obtained after oxidation is pure iron, which can be further processed into steel.
Therefore, the production of steel from haematite ore involves a two-step process: reduction to obtain iron followed by oxidation to remove impurities and obtain pure iron. This process of reduction followed by oxidation is essential in the production of high-quality steel with the desired properties.
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The chemical process in the production of steel from haematite ore involve: [JEE 2000 Qualifying]a)Reductionb)Oxidationc)Reduction followed by oxidationd)Oxidation follwed by reductionCorrect answer is option 'C'. Can you explain this answer?
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