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A body of mass 0.40 kg moving initially with a constant speed of 10m/s to the north is subject to a constant force of 8.0 N directed towards the south for 30 sec. take the instant the force is applied to be t=0 , the position of the body at that time to be x=0 , predict its position at t=-5 sec?
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A body of mass 0.40 kg moving initially with a constant speed of 10m/s...
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A body of mass 0.40 kg moving initially with a constant speed of 10m/s...
Initial Conditions:
- Mass of the body (m) = 0.40 kg
- Initial speed of the body (v) = 10 m/s (to the north)
- Force applied (F) = 8.0 N (directed towards the south)
- Time at which force is applied (t) = 0 s
- Initial position of the body (x) = 0 m
Using Newton's Second Law:
According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, it can be represented as:
F = ma
Calculating Acceleration:
Given that the mass of the body is 0.40 kg and the force applied is 8.0 N, we can calculate the acceleration as follows:
a = F/m = 8.0 N / 0.40 kg = 20 m/s²
Calculating Displacement:
The displacement of an object can be calculated using the equation of motion:
x = x₀ + v₀t + (1/2)at²
Since the body is initially at x₀ = 0 m and has an initial speed v₀ = 10 m/s to the north, we can substitute these values into the equation:
x = 0 + (10 m/s)(t) + (1/2)(20 m/s²)(t²)
x = 10t + 10t²
Predicting the Position at t = -5 sec:
To predict the position of the body at t = -5 sec, we substitute t = -5 sec into the equation:
x = 10(-5) + 10(-5)²
x = -50 + 10(25)
x = -50 + 250
x = 200 m
Explanation:
The body is initially moving with a constant speed of 10 m/s to the north. When a constant force of 8.0 N is applied towards the south for 30 seconds, the body experiences an acceleration of 20 m/s² in the opposite direction. Using the equation of motion, we can calculate the displacement of the body at any given time.
In this case, we are predicting the position of the body at t = -5 sec. By substituting t = -5 sec into the equation, we find that the body would be at a position of 200 m. The negative sign indicates that the body has moved 200 m to the south from its initial position.
Therefore, according to the given conditions, the predicted position of the body at t = -5 sec is 200 m to the south of its initial position.
- Mass of the body (m) = 0.40 kg
- Initial speed of the body (v) = 10 m/s (to the north)
- Force applied (F) = 8.0 N (directed towards the south)
- Time at which force is applied (t) = 0 s
- Initial position of the body (x) = 0 m
Using Newton's Second Law:
According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. Mathematically, it can be represented as:
F = ma
Calculating Acceleration:
Given that the mass of the body is 0.40 kg and the force applied is 8.0 N, we can calculate the acceleration as follows:
a = F/m = 8.0 N / 0.40 kg = 20 m/s²
Calculating Displacement:
The displacement of an object can be calculated using the equation of motion:
x = x₀ + v₀t + (1/2)at²
Since the body is initially at x₀ = 0 m and has an initial speed v₀ = 10 m/s to the north, we can substitute these values into the equation:
x = 0 + (10 m/s)(t) + (1/2)(20 m/s²)(t²)
x = 10t + 10t²
Predicting the Position at t = -5 sec:
To predict the position of the body at t = -5 sec, we substitute t = -5 sec into the equation:
x = 10(-5) + 10(-5)²
x = -50 + 10(25)
x = -50 + 250
x = 200 m
Explanation:
The body is initially moving with a constant speed of 10 m/s to the north. When a constant force of 8.0 N is applied towards the south for 30 seconds, the body experiences an acceleration of 20 m/s² in the opposite direction. Using the equation of motion, we can calculate the displacement of the body at any given time.
In this case, we are predicting the position of the body at t = -5 sec. By substituting t = -5 sec into the equation, we find that the body would be at a position of 200 m. The negative sign indicates that the body has moved 200 m to the south from its initial position.
Therefore, according to the given conditions, the predicted position of the body at t = -5 sec is 200 m to the south of its initial position.
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A body of mass 0.40 kg moving initially with a constant speed of 10m/s to the north is subject to a constant force of 8.0 N directed towards the south for 30 sec. take the instant the force is applied to be t=0 , the position of the body at that time to be x=0 , predict its position at t=-5 sec?
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A body of mass 0.40 kg moving initially with a constant speed of 10m/s to the north is subject to a constant force of 8.0 N directed towards the south for 30 sec. take the instant the force is applied to be t=0 , the position of the body at that time to be x=0 , predict its position at t=-5 sec? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body of mass 0.40 kg moving initially with a constant speed of 10m/s to the north is subject to a constant force of 8.0 N directed towards the south for 30 sec. take the instant the force is applied to be t=0 , the position of the body at that time to be x=0 , predict its position at t=-5 sec? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 0.40 kg moving initially with a constant speed of 10m/s to the north is subject to a constant force of 8.0 N directed towards the south for 30 sec. take the instant the force is applied to be t=0 , the position of the body at that time to be x=0 , predict its position at t=-5 sec?.
A body of mass 0.40 kg moving initially with a constant speed of 10m/s to the north is subject to a constant force of 8.0 N directed towards the south for 30 sec. take the instant the force is applied to be t=0 , the position of the body at that time to be x=0 , predict its position at t=-5 sec? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body of mass 0.40 kg moving initially with a constant speed of 10m/s to the north is subject to a constant force of 8.0 N directed towards the south for 30 sec. take the instant the force is applied to be t=0 , the position of the body at that time to be x=0 , predict its position at t=-5 sec? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 0.40 kg moving initially with a constant speed of 10m/s to the north is subject to a constant force of 8.0 N directed towards the south for 30 sec. take the instant the force is applied to be t=0 , the position of the body at that time to be x=0 , predict its position at t=-5 sec?.
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