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Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer?.

Solutions for Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Equilibrium constant for the reactionPCL5⇋PCL3+CL2 is 0.0205 at 230°C and 1 atmospheric pressure if at equilibrium concentration ofPCL5 is 0.235 molesliter−1liter-1and that ofCL2= 0.028 moleslit−1lit-1then conc. ofPCL3 at equilibrium isa)0.0174b)0.174c)0.0348d)1.74Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 11 tests.