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The isentropic enthalpy drop in moving blade is two-third of the isentropic enthalpy drop in fixed blades of a turbine. The degree of reaction will be
  • a)
    0.4
  • b)
    1
  • c)
    2/3
  • d)
    1/3
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The isentropic enthalpy drop in moving blade is two-third of the isent...
Isentropic Enthalpy Drop in Moving Blades and Fixed Blades

The isentropic enthalpy drop in the moving blades and fixed blades of a turbine can be related based on the degree of reaction.

Degree of Reaction
The degree of reaction (R) in a turbine is defined as the ratio of the enthalpy drop in the moving blades (h2 - h3) to the total enthalpy drop in the turbine (h1 - h3). It represents the proportion of enthalpy drop that occurs in the moving blades compared to the total enthalpy drop.

Relationship between Isentropic Enthalpy Drops
According to the given information, the isentropic enthalpy drop in the moving blades (h2 - h3) is two-thirds of the isentropic enthalpy drop in the fixed blades (h1 - h2). Let's represent the isentropic enthalpy drop in the fixed blades as x.

Isentropic enthalpy drop in moving blades = (2/3) * x
Isentropic enthalpy drop in fixed blades = x

Relationship between Degree of Reaction and Isentropic Enthalpy Drops
The degree of reaction (R) can be calculated as follows:

R = (h2 - h3) / (h1 - h3)

Substituting the given relationship between isentropic enthalpy drops:

R = ((2/3) * x) / (x + ((2/3) * x))
R = ((2/3) * x) / ((3/3) * x)
R = (2/3)

Therefore, the degree of reaction (R) is 0.4.

Conclusion
The correct answer is option 'A' (0.4), which represents the degree of reaction. The given relationship between the isentropic enthalpy drops in the moving blades and fixed blades allows us to calculate the degree of reaction, which is 0.4.
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Community Answer
The isentropic enthalpy drop in moving blade is two-third of the isent...
Degree of reaction = isentropic enthalpy drop in moving blade/(isentropic enthalpy drop in fixed blade+isentropic enthalpy drop in moving blade).
= (2/3)/[1+(2/3)].

= (2/3)/(5/3),

= 2/5,

DOR = 0.4 

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The isentropic enthalpy drop in moving blade is two-third of the isentropic enthalpy drop in fixed blades of a turbine. The degree of reaction will bea)0.4b)1c)2/3d)1/3Correct answer is option 'A'. Can you explain this answer?
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