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 The general solution of (x2 D2 – xD), y= 0 is :
  • a)
    y = C1 + Cex
  • b)
     y = C1 + Cx
  • c)
     y = C1 + Cx2
  • d)
    y = C1 x + Cx2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C...
+ 3xD + 2)y = 0 is given by:

y = c1e-2x + c2e-x

where c1 and c2 are constants determined by initial/boundary conditions.
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Community Answer
The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C...
D(D - 1) - D = 0

D2 - 2D =0

D(D - 2) = 0

so D = o or D = 2

y = C1 + C2X2
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The general solution of(x2D2– xD), y=0 is :a)y = C1+ C2exb)y = C1+ C2xc)y = C1+ C2x2d)y = C1x +C2x2Correct answer is option 'C'. Can you explain this answer?
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