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If u=a/r6-b/r12, find out value of x at the equilibrium as potential energy of the particle at equilibrium?
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If u=a/r6-b/r12, find out value of x at the equilibrium as potential e...
At equilibrium, net force =zeroSo, dU/dr=0(as F=dU/dr) dU/dr=6a/r^7-12b/r^13=0 , so, r^6=2b/a , Now putting this value, U=a/r^6-b/r^12, U=a^2/4b
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If u=a/r6-b/r12, find out value of x at the equilibrium as potential energy of the particle at equilibrium?
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