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A particle of charge q and mass m moves in a circular orbit of radius r with angular speed. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on
  • a)
    q and m
  • b)
    ω and q
  • c)
    ω, q and m
  • d)
    ω and m
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A particle of charge q and mass m moves in a circular orbit of radius ...
To find the magnetic moment due to a single particle, it is advisable to consider the equivalent current due to it
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Most Upvoted Answer
A particle of charge q and mass m moves in a circular orbit of radius ...
Explanation:
When a charged particle moves in a circular path, it generates a magnetic field perpendicular to the plane of its orbit. This magnetic field is proportional to the magnitude of the particle's velocity and the magnitude of its charge. The particle also has an angular momentum due to its rotation around the center of the circular path.

The magnetic moment of the particle is defined as the product of the magnitude of its charge and the magnitude of its angular momentum. Therefore, the ratio of the magnitude of its magnetic moment to that of its angular momentum can be written as:

μ/L = q/2m

where μ is the magnetic moment, L is the angular momentum, q is the charge, and m is the mass of the particle.

This ratio depends only on the charge and mass of the particle, and is independent of the radius of the circular path or the angular speed of the particle.

Hence, option 'A' is the correct answer.
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