A reaction follows second order rate law,a)A plot of [A] versus t is a straight lineb)A plot of 1/[A] versus t is a straight line.c)A plot of ln[A] versus t is a straight line.d)A plot of e[A] versus t is a straight line.Correct answer is option 'B'. Can you explain this answer?

Question

Answer

1/(a•-x) - 1/a• = kt ... equation 1
a• (a not)= initial concentration of reactant at t=0
1/(a•-x) = 1/[A] So, equation 1 can be written as
1/[A] = kt + 1/a•
Compare this with, y = mx + c
This equation will give you a straight line with intercept = 1/a• and slope = k

Answer

For second order reaction kt= x/a(a-x) . So 1/a vs t is a straight line.

Answer

Answer 1is right

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