What is the relationship between Emand E0a)Em=-0.537 E0b)Em=-0....
peak value Em=2E0/π
so 2/π value is 0.637
therefore,
Em=-0.637 E0
What is the relationship between Emand E0a)Em=-0.537 E0b)Em=-0....
Relationship between Em and E0
The relationship between Em and E0 is important in electrochemistry as it helps to determine the standard electrode potential (E0) of a half-cell reaction from its measured electrode potential (Em).
The equation that relates Em to E0 is known as the Nernst equation, which is given as:
Em = E0 - (RT/nF) ln(Q)
Where:
Em = Measured electrode potential
E0 = Standard electrode potential
R = Gas constant (8.314 J/K mol)
T = Temperature in Kelvin
n = Number of electrons transferred in the half-reaction
F = Faraday constant (96,485 C/mol)
ln = Natural logarithm
Q = Reaction quotient
The value of E0 can be calculated using the Nernst equation when the values of Em, R, T, n, F, and Q are known.
Options provided in the question:
a) Em = -0.537 E0
b) Em = -0.737 E0
c) Em = -0.637 E0 (Correct answer)
d) Em = -0.707 E0
Among the given options, the correct relationship between Em and E0 is option 'c', where Em = -0.637 E0. This means that the measured electrode potential (Em) is approximately two-thirds of the standard electrode potential (E0) for the given half-cell reaction.
This relationship can be used to determine E0 from Em or vice versa. It is important to note that the Nernst equation assumes that the half-cell reaction is at equilibrium and that the concentrations of the reactants and products are known.