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A wedge of mass M is fitted with a spring of stiffness ‘k’ is kept on a smooth horizontal surface. A rod of mass m is kept on the wedge as shown in the figure. System is in equilibrium.
Assuming that all surfaces are smooth, the potential energy stored in the spring is:
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A wedge of mass M is fitted with a spring of stiffness ‘k’...
N sinθ = kx
N cosθ = mg
We get the value of x, 
x = (mg tanθ) / k
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Most Upvoted Answer
A wedge of mass M is fitted with a spring of stiffness ‘k’...
N sinθ = kx
N cosθ = mg
We get the value of x, 
x = (mg tanθ) / k
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Community Answer
A wedge of mass M is fitted with a spring of stiffness ‘k’...
As Normal is perpendicular to the surface the cos component of N is equals to mg and sin component of N is equals to Kx therefore N sin theta component is equal to k X. By this we can find out and N is equals to mg /cos theta now by putting it the equation we will find out X is equals to mg tan theta/k then by conserving the energy by conservation of mechanical energy will find out that have 1/2Kx square is equal to half into m2g2 tan theta .Then by simplifying the answer we will find out the potential energy of the spring that is half K x square is equals to m2 g square 10 theta by 2.
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