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What should be taken away from 3x2−− 4y2+ 5xy+ 20 to obtain−−x2−−y2+ 6xy+ 20?
  • a)
    4x2−− 5y2−−xy
  • b)
    4x2−− 3y2−−xy
  • c)
    4x2−− 3y2−− 7xy
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
What should be taken away from 3x2−−4y2+5xy+20 to obtain&m...
3x- 4y+ 5xy + 20-  (-x- y+ 6xy+20)
=3x- 4y+ 5xy + 20 + x2 + y- 6xy-20)
=4x2-3y2-xy
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Most Upvoted Answer
What should be taken away from 3x2−−4y2+5xy+20 to obtain&m...
3x- 4y+ 5xy + 20-  (-x- y+ 6xy+20)
=3x- 4y+ 5xy + 20 + x2 + y- 6xy-20)
=4x2-3y2-xy
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Community Answer
What should be taken away from 3x2−−4y2+5xy+20 to obtain&m...
The equation 3x2 can be interpreted as "3 multiplied by 2." Therefore, the answer would be 6.
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