Class 12 Exam > Class 12 Questions > The complex, [Ni(CN)4]2-, has:a)Octahedral st...
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The complex, [Ni(CN)4]2-, has:
- a)Octahedral structure
- b)Linear structure
- c)Tetrahedral structure
- d)Square planar Structure
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
The complex, [Ni(CN)4]2-, has:a)Octahedral structureb)Linear structure...
In case of [Ni(CN)4 ]^2-, oxidation state of Nickel is +2. So, Ni^2+ : 3d^8 4s^0 . Now, cyanide also causes pairing of unpaired electrons, in 3d orbital, all the 8 electrons will get paired, so now, 1 more orbital is left.... and there are 4 ligands to bond with. Hence, the hybridization will be dsp^2 so hence, it is a square planar complex because all dsp^2 complexes are square planar. The singly unpaired electron will pair up only if the ligand field is very strong and that too only in the lower energy orbitals.
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The complex, [Ni(CN)4]2-, has:a)Octahedral structureb)Linear structure...
[Ni(CN)4]2− is a square planar geometry formed by dsp2 hybridisation. [Ni(CN)4]2− is diamagnetic, so Ni2+ ion has 38 outer configurations with two unpaired electrons.
For the formation of the square planar structure by dsp2 hybridisation, two unpaired d-electrons are paired up due to energy made available by the approach of ligands, making one of the 3d orbitals empty.
For the formation of the square planar structure by dsp2 hybridisation, two unpaired d-electrons are paired up due to energy made available by the approach of ligands, making one of the 3d orbitals empty.
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The complex, [Ni(CN)4]2-, has:a)Octahedral structureb)Linear structure...
The complex, [Ni(CN)4]2-, has a square planar structure.
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The complex, [Ni(CN)4]2-, has:a)Octahedral structureb)Linear structurec)Tetrahedral structured)Square planar StructureCorrect answer is option 'D'. Can you explain this answer?
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