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A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes upto 2 m height further, find the magnitude of the force. Consider g = 10 m/s2.                                    
[AIEEE 2006]
  • a)
     4 N 
  • b)
    16 N
  • c)
     20 N
  • d)
    22 N
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A ball of mass 0.2 kg is thrown vertically upwards by applying a force...
The situation is shown in figure. At initial time, the ball is at P, then under the action of a force (exerted by hand) from P to A and then from A to B let acceleration of ball during PA is a ms-2 [assumed to be constant] in upward direction and velocity of ball at A is v m/s.
Then for PA, v2 = 02 +2a × 0.2
For AB, 0 = v2 - 2×g×2 => v2 = 2g × 2
From above equations,
a = 10g =100ms-2
Then for PA, FBD of ball is  F - mg = ma
[F is the force exted by hand on ball] => F = m(g+a) = 0.2(11g)
= 22 N
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Most Upvoted Answer
A ball of mass 0.2 kg is thrown vertically upwards by applying a force...
WORK DONE = POTENTIAL ENERGY
F*s = mgh
force= 0.2*10*2.2/0.2
         = 22N
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Community Answer
A ball of mass 0.2 kg is thrown vertically upwards by applying a force...
To find the magnitude of the force applied to the ball, we can use the concept of work done. Work done is given by the equation:

Work = Force × Distance

In this case, the distance is given as 0.2 m, and we need to find the force.

We know that the work done on the ball is equal to the change in its potential energy. When the ball is thrown upwards, it gains potential energy equal to its mass multiplied by the acceleration due to gravity (g) and the height it reaches (2 m). So, the work done is:

Work = mgh

where m is the mass of the ball, g is the acceleration due to gravity, and h is the height reached by the ball.

Given that the mass of the ball is 0.2 kg and g is 10 m/s^2, we can calculate the work done:

Work = 0.2 kg × 10 m/s^2 × 2 m = 4 J

Since work done is equal to the force multiplied by the distance, we can write:

Force × Distance = 4 J

Rearranging the equation, we get:

Force = 4 J / Distance

Substituting the values, we have:

Force = 4 J / 0.2 m = 20 N

Therefore, the magnitude of the force applied to the ball is 20 N.
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A ball of mass 0.2 kg is thrown vertically upwards by applying a force by hand. If the hand moves 0.2 m while applying the force and the ball goes upto 2 m height further, find the magnitude of the force. Consider g = 10 m/s2. [AIEEE 2006]a)4 Nb)16 Nc)20 Nd)22 NCorrect answer is option 'D'. Can you explain this answer?
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