Oxidation in Daniel Cell

In a Daniel cell, oxidation occurs at the anode. Let's understand why this is the correct answer.

The Daniel Cell
The Daniel cell is an electrochemical cell that consists of two half-cells connected by a salt bridge. The two half-cells are the anode and the cathode, which are immersed in their respective electrolyte solutions. The anode is typically made of zinc, while the cathode is made of copper.

Redox Reactions
In an electrochemical cell, a redox (reduction-oxidation) reaction takes place. This reaction involves the transfer of electrons between species, resulting in the oxidation of one species and the reduction of another. In the Daniel cell, the redox reaction occurs at the anode and the cathode.

Anode and Cathode Reactions
At the anode (negative electrode), oxidation occurs. The zinc electrode undergoes oxidation, losing electrons and forming zinc ions. This can be represented by the following half-reaction:

Zn(s) -> Zn2+(aq) + 2e-

At the cathode (positive electrode), reduction occurs. The copper ions from the copper sulfate solution gain electrons and are reduced to form copper atoms, which deposit onto the copper electrode. This can be represented by the following half-reaction:

Cu2+(aq) + 2e- -> Cu(s)

Electron Flow
During the redox reaction, electrons flow from the anode to the cathode through an external circuit. This electron flow produces an electric current that can be used to do work.

Direction of Electron Flow
Since oxidation occurs at the anode, electrons are released from the anode and flow towards the cathode. This direction of electron flow determines the direction of the current in the external circuit.

Conclusion
In summary, in a Daniel cell, oxidation takes place at the anode. The zinc electrode undergoes oxidation, losing electrons and forming zinc ions. The electrons flow from the anode to the cathode through an external circuit, producing an electric current. At the cathode, reduction occurs, and copper ions are reduced to form copper atoms. Therefore, the correct answer is option C - anode.