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Find distance of point A(2,3) measured parallel to the line x- y=5 from the line 2x+y+6=0.?
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Find distance of point A(2,3) measured parallel to the line x- y=5 fro...
Given information:
- Point A is located at coordinates (2,3).
- The equation of the line parallel to x-y=5 is given as 2x+y-6=0.

Steps to find the distance:

Step 1: Find the coordinates of the point on the line x-y=5 that is parallel to point A.
To find the coordinates of the point on the line x-y=5 that is parallel to point A, we need to consider the slope of the line x-y=5.
The given line can be rearranged in the slope-intercept form (y = mx + c) by adding y to both sides:
x - y = 5
-y = -x + 5
y = x - 5

From this equation, we can observe that the slope of the line is 1 (as the coefficient of x is 1).
Since the line parallel to x-y=5 should have the same slope, the equation of the parallel line passing through point A can be written as:
y = x - c

To find the value of c, we substitute the coordinates of point A (2,3) into the equation:
3 = 2 - c
c = 2 - 3
c = -1

So, the equation of the line parallel to x-y=5 passing through point A is y = x - 1.

Step 2: Find the intersection point of the two lines.
To find the intersection point of the lines 2x+y-6=0 and y=x-1, we can solve the system of equations formed by these two lines.
Substituting the value of y from the second equation into the first equation, we get:
2x + (x - 1) - 6 = 0
3x - 7 = 0
3x = 7
x = 7/3

Substituting this value of x into the second equation, we can find the value of y:
y = 7/3 - 1
y = 7/3 - 3/3
y = 4/3

So, the intersection point of the two lines is (7/3, 4/3).

Step 3: Find the distance between point A and the intersection point.
To find the distance between point A and the intersection point, we can use the distance formula:
Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Substituting the coordinates of point A (2,3) and the intersection point (7/3, 4/3) into the distance formula, we get:
Distance = sqrt((7/3 - 2)^2 + (4/3 - 3)^2)
Distance = sqrt((7/3 - 6/3)^2 + (4/3 - 9/3)^2)
Distance = sqrt((1/3)^2 + (-5/3)^2)
Distance = sqrt(1/9 + 25/9)
Distance = sqrt(26/9)
Distance = sqrt(26)/3

Therefore, the distance of point A(2,3) measured parallel to the line x-y=5 from the line 2x+y-6=0 is sqrt(
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Find distance of point A(2,3) measured parallel to the line x- y=5 from the line 2x+y+6=0.?
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Find distance of point A(2,3) measured parallel to the line x- y=5 from the line 2x+y+6=0.? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Find distance of point A(2,3) measured parallel to the line x- y=5 from the line 2x+y+6=0.? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find distance of point A(2,3) measured parallel to the line x- y=5 from the line 2x+y+6=0.?.
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