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The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρ will be
- a)0.5 R
- b)1.5 R
- c)2.5 R
- d)2.2 R
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then C`...
We know that,
Cp=cv+R
E=3Rt/2
also,
E=Cv
cp=R+3RT/2
=5/2 RT
=2.5R
Cp=cv+R
E=3Rt/2
also,
E=Cv
cp=R+3RT/2
=5/2 RT
=2.5R
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The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then C`...
Explanation:
- The kinetic energy of one mole of an ideal gas is given by E = 3/2 RT, where R is the gas constant and T is the temperature in Kelvin.
- The specific heat capacity of a gas at constant volume (Cv) is defined as the amount of heat required to raise the temperature of one mole of the gas by one degree while keeping the volume constant.
- The specific heat capacity of a gas at constant pressure (Cp) is defined as the amount of heat required to raise the temperature of one mole of the gas by one degree while keeping the pressure constant.
- The relationship between Cp and Cv is given by Cp - Cv = R, where R is the gas constant.
- Using the above equation, we can calculate the value of Cp in terms of Cv and R as Cp = Cv + R.
- Now, we can substitute the value of Cv from the ideal gas law as Cv = (3/2) R, and the value of R from the same law as R = (Nk)/V, where N is the number of moles, k is the Boltzmann constant, and V is the volume.
- Substituting these values in the equation for Cp, we get Cp = (5/2) R = 2.5 R.
- Therefore, the correct answer is option C, 2.5 R.
- The kinetic energy of one mole of an ideal gas is given by E = 3/2 RT, where R is the gas constant and T is the temperature in Kelvin.
- The specific heat capacity of a gas at constant volume (Cv) is defined as the amount of heat required to raise the temperature of one mole of the gas by one degree while keeping the volume constant.
- The specific heat capacity of a gas at constant pressure (Cp) is defined as the amount of heat required to raise the temperature of one mole of the gas by one degree while keeping the pressure constant.
- The relationship between Cp and Cv is given by Cp - Cv = R, where R is the gas constant.
- Using the above equation, we can calculate the value of Cp in terms of Cv and R as Cp = Cv + R.
- Now, we can substitute the value of Cv from the ideal gas law as Cv = (3/2) R, and the value of R from the same law as R = (Nk)/V, where N is the number of moles, k is the Boltzmann constant, and V is the volume.
- Substituting these values in the equation for Cp, we get Cp = (5/2) R = 2.5 R.
- Therefore, the correct answer is option C, 2.5 R.
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The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρwill bea)0.5 Rb)1.5 Rc)2.5 Rd)2.2 RCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρwill bea)0.5 Rb)1.5 Rc)2.5 Rd)2.2 RCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρwill bea)0.5 Rb)1.5 Rc)2.5 Rd)2.2 RCorrect answer is option 'C'. Can you explain this answer?.
The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρwill bea)0.5 Rb)1.5 Rc)2.5 Rd)2.2 RCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρwill bea)0.5 Rb)1.5 Rc)2.5 Rd)2.2 RCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρwill bea)0.5 Rb)1.5 Rc)2.5 Rd)2.2 RCorrect answer is option 'C'. Can you explain this answer?.
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