JEE Exam > JEE Questions > With oxalic acid, glycerol at 503 K givesa) ...
Start Learning for Free
With oxalic acid, glycerol at 503 K gives
- a)Allyl alcohol
- b)Formic acid
- c)Glyceraldehyde
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
With oxalic acid, glycerol at 503 K givesa) ...
At 110⁰C glycerol reacts with oxalic acid giving formic acid. But heating at 260⁰C results allyl alcohol.
View all questions of this test
Most Upvoted Answer
With oxalic acid, glycerol at 503 K givesa) ...
When glycerol is reacted with Oxalic acid at 383K, it gives formic acid as follows:
CH2OH-CHOH-CH2OH + COOH-COOH ------> CH2OH-CHOH-CH2OH + HCOOH at 383K
. The glycerine is used in excess amounts and hence obtained in products also.
But when , it is heated with Oxalic acid at 503K, it gives allyl alcohol,
i.e. those alcohols in which OH group attached to carbon is sp3 hybridised but the sp3 hybridised carbon is attached to sp2 hybridised carbon atom.Allyl alcohol is CH2=CH-CH2OH.
CH2OH-CHOH-CH2OH + COOH-COOH ------> CH2OH-CHOH-CH2OH + HCOOH at 383K
. The glycerine is used in excess amounts and hence obtained in products also.
But when , it is heated with Oxalic acid at 503K, it gives allyl alcohol,
i.e. those alcohols in which OH group attached to carbon is sp3 hybridised but the sp3 hybridised carbon is attached to sp2 hybridised carbon atom.Allyl alcohol is CH2=CH-CH2OH.
Free Test
FREE
| Start Free Test |
Community Answer
With oxalic acid, glycerol at 503 K givesa) ...
Oxalic acid is a dicarboxylic acid with the chemical formula C2H2O4. It has two carboxylic acid functional groups, which can undergo various reactions under different conditions. One such reaction is the reaction of oxalic acid with glycerol at a high temperature of 503 K.
The reaction between oxalic acid and glycerol involves the formation of an ester. An ester is a compound formed by the condensation of an alcohol and an acid, with the elimination of water. In this case, the ester formed is allyl oxalate.
The reaction can be represented as follows:
Oxalic acid + Glycerol → Allyl Oxalate + Water
Now, let's understand why the correct answer is option 'A' - Allyl alcohol.
1. Formation of Allyl Oxalate:
The reaction between oxalic acid and glycerol at 503 K leads to the formation of allyl oxalate. This is an ester formed by the condensation of the hydroxyl group of glycerol and the carboxyl group of oxalic acid.
2. Decomposition of Allyl Oxalate:
Allyl oxalate undergoes thermal decomposition at high temperatures, such as 503 K. This decomposition reaction leads to the formation of allyl alcohol and carbon dioxide.
3. Allyl Alcohol:
Allyl alcohol is the final product obtained from the reaction of oxalic acid with glycerol at 503 K. It is an unsaturated alcohol with the chemical formula C3H6O. Allyl alcohol is a colorless liquid with a pungent odor.
In conclusion, the correct answer is option 'A' - Allyl alcohol. The reaction between oxalic acid and glycerol at 503 K initially forms allyl oxalate, which then decomposes to yield allyl alcohol and carbon dioxide.
The reaction between oxalic acid and glycerol involves the formation of an ester. An ester is a compound formed by the condensation of an alcohol and an acid, with the elimination of water. In this case, the ester formed is allyl oxalate.
The reaction can be represented as follows:
Oxalic acid + Glycerol → Allyl Oxalate + Water
Now, let's understand why the correct answer is option 'A' - Allyl alcohol.
1. Formation of Allyl Oxalate:
The reaction between oxalic acid and glycerol at 503 K leads to the formation of allyl oxalate. This is an ester formed by the condensation of the hydroxyl group of glycerol and the carboxyl group of oxalic acid.
2. Decomposition of Allyl Oxalate:
Allyl oxalate undergoes thermal decomposition at high temperatures, such as 503 K. This decomposition reaction leads to the formation of allyl alcohol and carbon dioxide.
3. Allyl Alcohol:
Allyl alcohol is the final product obtained from the reaction of oxalic acid with glycerol at 503 K. It is an unsaturated alcohol with the chemical formula C3H6O. Allyl alcohol is a colorless liquid with a pungent odor.
In conclusion, the correct answer is option 'A' - Allyl alcohol. The reaction between oxalic acid and glycerol at 503 K initially forms allyl oxalate, which then decomposes to yield allyl alcohol and carbon dioxide.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer?
Question Description
With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer?.
With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer?.
Solutions for With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer?, a detailed solution for With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice With oxalic acid, glycerol at 503 K givesa) Allyl alcohol b) Formic acid c) Glyceraldehyde d) None of these Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup