All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  Section 1Q. No. 1 - 8 Carry 4 marks eachThe a... Start Learning for Free
Section 1
Q. No. 1 - 8 Carry 4 marks each
The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.
Q.
An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of the
electron in this state is pπa0 (where a0 is the Bohr radius). The value of p is
    Correct answer is '2'. Can you explain this answer?
    Clear all your JEE doubts with EduRev
    Most Upvoted Answer
    Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is...
    Free Test
    FREE
    Start Free Test
    		Start Free Test
    Community Answer
    Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is...
    Explore Courses for JEE exam

    Similar JEE Doubts

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    The French physicist Louis de-Broglie in 1924 postulated that matter, like radiation, should exhibit a dual behaviour. He proposed the following relationship between the wavelength of a material particle, its linear momentum p and planck constant h.The de Broglie relation implies that the wavelength of a particle should decreases as its velocity increases. It also implies that for a given velocity heavier particles should have shorter wavelength than lighter particles. The waves associated with particles in motion are called matter waves or de Broglie waves.These waves differ from the electromagnetic waves as they,(i) have lower velocities(ii) have no electrical and magnetic fields and(iii) are not emitted by the particle under consideration.The experimental confirmation of the deBroglie relation was obtained when Davisson and Germer, in 1927, observed that a beam of electrons is diffracted by a nickel crystal. As diffraction is a characteristic property of waves, hence the beam of electron behaves as a wave, as proposed by deBroglie.Werner Heisenberg considered the limits of how precisely we can measure properties of an electron or other microscopic particle like electron. He determined that there is a fundamental limit of how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse is also ture. This is summed up in what we now call the Heisenberg uncertainty principle : It is impossible to determine simultaneously and precisely both the momentum and position of a particle. The product of undertainty in the position, x and the uncertainity in the momentum (mv) must be greater than or equal to h/4. i.e.Q. The transition, so that the de - Broglie wavelength of electron becomes 3 times of its initial value in He+ ion will be

    Top Courses for JEEView all

    Top Courses for JEE

    Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer?
    Question Description
    Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer?.
    Solutions for Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer?, a detailed solution for Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer? has been provided alongside types of Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of theelectron in this state is pπa0 (where a0 is the Bohr radius). The value of p isCorrect answer is '2'. Can you explain this answer? tests, examples and also practice JEE tests.
    Explore Courses for JEE exam

    Top Courses for JEE

    Explore Courses
    SaveJoin the Discussion on the App for FREE
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev
    Get App
    © EduRev
    Education Revolution
    Signup to see your scores go up within 7 days!
    Access 1000+ FREE Docs, Videos and Tests
    Takes less than 10 seconds to signup