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The function F(x) = x sin x satisfies the following equations:  f" (x) + f(x) + t cos x= 0. The value of t is 
    Correct answer is '-2'. Can you explain this answer?
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    The function F(x) = x sin x satisfies the following equations: f"...
    F(x)=xsin(x) f'(x)=xcos(x)+sin(x) f"(x)=-xsin(x)+2cos(x) Now coming to the question, f"(x)+f(x)+tcos(x)=0 =>-xsin(x)+2cos(x)+xsin(x)+tcos(x)=0 =>2cos(x)+tcos(x)=0 =>either cos(x)=0 or 2+t=0 =>2+t=0 t=-2
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    The function F(x) = x sin x satisfies the following equations: f" (x) + f(x) + t cos x= 0. The value of t isCorrect answer is '-2'. Can you explain this answer?
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