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Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)
- a)2x -19= 0
- b)2x +19= 0
- c)3x -19= 0
- d)3x +19= 0
Correct answer is option 'C'. Can you explain this answer?
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Find the equation of the bisector of the angle between the lines x+2y&...
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Find the equation of the bisector of the angle between the lines x+2y&...
The given lines are:
L1: x - 2y = 0
L2: x + 2y = 0
To find the equation of the bisector of the angle between these lines, we need to find the slope of the bisector.
The slope of L1 is given by m1 = 2 (the coefficient of y when the equation is in the form y = mx + b).
The slope of L2 is given by m2 = -2.
The slope of the bisector, m, can be found using the formula:
m = (m1 + m2) / 2
m = (2 + (-2)) / 2
m = 0 / 2
m = 0
The slope of the bisector is 0.
To find the equation of the bisector, we need a point that lies on it. Let's find the point of intersection of the given lines:
Solving the two equations simultaneously, we get:
x - 2y = 0
x + 2y = 0
Adding the two equations, we get:
2x = 0
x = 0
Substituting x = 0 into either of the equations, we get:
2(0) = 0
0 = 0
Therefore, the lines intersect at the point (0, 0).
Now we have a point (0, 0) that lies on the bisector and the slope of the bisector is 0.
Using the point-slope form of a line, the equation of the bisector is:
y - y1 = m(x - x1)
Substituting the values, we get:
y - 0 = 0(x - 0)
y = 0
Therefore, the equation of the bisector of the angle between the lines x - 2y = 0 and x + 2y = 0 is y = 0.
L1: x - 2y = 0
L2: x + 2y = 0
To find the equation of the bisector of the angle between these lines, we need to find the slope of the bisector.
The slope of L1 is given by m1 = 2 (the coefficient of y when the equation is in the form y = mx + b).
The slope of L2 is given by m2 = -2.
The slope of the bisector, m, can be found using the formula:
m = (m1 + m2) / 2
m = (2 + (-2)) / 2
m = 0 / 2
m = 0
The slope of the bisector is 0.
To find the equation of the bisector, we need a point that lies on it. Let's find the point of intersection of the given lines:
Solving the two equations simultaneously, we get:
x - 2y = 0
x + 2y = 0
Adding the two equations, we get:
2x = 0
x = 0
Substituting x = 0 into either of the equations, we get:
2(0) = 0
0 = 0
Therefore, the lines intersect at the point (0, 0).
Now we have a point (0, 0) that lies on the bisector and the slope of the bisector is 0.
Using the point-slope form of a line, the equation of the bisector is:
y - y1 = m(x - x1)
Substituting the values, we get:
y - 0 = 0(x - 0)
y = 0
Therefore, the equation of the bisector of the angle between the lines x - 2y = 0 and x + 2y = 0 is y = 0.
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Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19= 0b)2x +19= 0c)3x -19= 0d)3x +19= 0Correct answer is option 'C'. Can you explain this answer?
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Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19= 0b)2x +19= 0c)3x -19= 0d)3x +19= 0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19= 0b)2x +19= 0c)3x -19= 0d)3x +19= 0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19= 0b)2x +19= 0c)3x -19= 0d)3x +19= 0Correct answer is option 'C'. Can you explain this answer?.
Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19= 0b)2x +19= 0c)3x -19= 0d)3x +19= 0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19= 0b)2x +19= 0c)3x -19= 0d)3x +19= 0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19= 0b)2x +19= 0c)3x -19= 0d)3x +19= 0Correct answer is option 'C'. Can you explain this answer?.
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