JEE Exam  >  JEE Questions  >  Find the equation of the bisector of the angl... Start Learning for Free
Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)
  • a)
    2x -19 = 0
  • b)
    2x + 19 = 0
  • c)
    3x -19 = 0
  • d)
    3x + 1 9= 0
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Find the equation of the bisector of the angle between the lines x+2y&...
Using formula given in synopsis
This question is part of UPSC exam. View all JEE courses
Most Upvoted Answer
Find the equation of the bisector of the angle between the lines x+2y&...
To find the equation of the bisector of the angle between two lines, we can follow these steps:

Step 1: Find the slopes of the given lines
The equation of the first line is x - 2y + 11 = 0
To find the slope of this line, we can rearrange the equation in the slope-intercept form (y = mx + c), where m is the slope:
2y = x + 11
y = (1/2)x + 11/2
Comparing with y = mx + c, we can see that the slope (m1) of this line is 1/2.

The equation of the second line is 3x - 6y + 5 = 0
To find the slope of this line, we can rearrange the equation in the slope-intercept form:
6y = 3x + 5
y = (1/2)x + 5/6
Comparing with y = mx + c, we can see that the slope (m2) of this line is 1/2.

Step 2: Find the angle between the lines
The angle between two lines with slopes m1 and m2 can be found using the formula:
tanθ = (m2 - m1) / (1 + m1m2)
In this case, the slopes are the same (m1 = m2 = 1/2), so the angle between the lines is 0 degrees.

Step 3: Find the slope of the bisector
The angle between the bisector and each line is half of the angle between the lines. Since the angle between the lines is 0 degrees, the angle between the bisector and each line is also 0 degrees. This means that the bisector is parallel to the given lines.

The slope of the bisector is the same as the slopes of the given lines, which is 1/2.

Step 4: Find the equation of the bisector
We know that the bisector passes through the point (1,3). We can use the point-slope form of a line to find the equation of the bisector:
y - y1 = m(x - x1)
where (x1, y1) is the point (1,3) and m is the slope of the bisector.

Plugging in the values, we get:
y - 3 = (1/2)(x - 1)
2y - 6 = x - 1
x - 2y + 5 = 0

Comparing with the given options, we can see that the correct equation of the bisector is 3x - 2y + 5 = 0, which matches with option 'C' (3x - 19 = 0).
Explore Courses for JEE exam
Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer?
Question Description
Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer?.
Solutions for Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer?, a detailed solution for Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Find the equation of the bisector of the angle between the lines x+2y–11=0, 3x–6y–5=0 which contains the point (1,–3)a)2x -19 = 0b)2x + 19 = 0c)3x -19 = 0d)3x + 1 9= 0Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev