A body is projected vertically upward with speed u. Find time taken by the body to reach half of its maximum height?





We need to find the time taken by the body to reach half of its maximum height. Let's first calculate the maximum height (H) reached by the body.

The maximum height (H) reached by the body can be calculated as:

H = (u^2)/(2g)

where u is the initial velocity of the body and g is the acceleration due to gravity.



Now, we need to find the time taken by the body to reach half of its maximum height (H/2).

Let t be the time taken by the body to reach half of its maximum height (H/2).

At the height H/2, the velocity of the body will be:

v = u - gt

where v is the velocity of the body at height H/2.



We know that at the maximum height (H), the velocity of the body becomes zero. Therefore, we can write:

0 = u - 2gt

t = u/2g



Therefore, the time taken by the body to reach half of its maximum height is:

t = u/2g

This is the required solution to the problem.



The time taken by the body to reach half of its maximum height is u/2g.

U^2sin^2¢÷4g