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pH of a saturated solution of Ba(OH)2 is 12. The value of solubility product (Ksp) of Ba(OH)2 is 
  • a)
    4.0 × 10–6
  • b)
    5.0 × 10–6
  • c)
    3.3 × 10–7
  • d)
    5.0 × 10–7
Correct answer is option 'D'. Can you explain this answer?
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pH of a saturated solution of Ba(OH)2is 12. The value of solubility pr...
The pH of a saturated solution of Ba(OH)2 is 12, which means it is basic.

The solubility product (Ksp) of Ba(OH)2 can be calculated using the following equation:

Ksp = [Ba2+][OH-]^2

Since the solution is saturated, the concentration of Ba2+ and OH- ions will be equal. Let's assume the concentration of both ions is x.

Therefore, Ksp = x * x^2 = x^3

Since the pH of the solution is 12, the concentration of OH- ions can be calculated using the equation:

pOH = 14 - pH
pOH = 14 - 12 = 2

Therefore, the concentration of OH- ions is 10^-2 M.

Since the concentration of OH- ions is equal to the concentration of Ba2+ ions, the concentration of Ba2+ ions is also 10^-2 M.

Substituting this value into the equation for Ksp:

Ksp = (10^-2) * (10^-2)^2 = 10^-2 * 10^-4 = 10^-6

Therefore, the value of the solubility product (Ksp) of Ba(OH)2 is 10^-6.
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pH of a saturated solution of Ba(OH)2is 12. The value of solubility product (Ksp) of Ba(OH)2isa)4.0 × 10–6b)5.0 × 10–6c)3.3 × 10–7d)5.0 × 10–7Correct answer is option 'D'. Can you explain this answer?
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pH of a saturated solution of Ba(OH)2is 12. The value of solubility product (Ksp) of Ba(OH)2isa)4.0 × 10–6b)5.0 × 10–6c)3.3 × 10–7d)5.0 × 10–7Correct answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about pH of a saturated solution of Ba(OH)2is 12. The value of solubility product (Ksp) of Ba(OH)2isa)4.0 × 10–6b)5.0 × 10–6c)3.3 × 10–7d)5.0 × 10–7Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for pH of a saturated solution of Ba(OH)2is 12. The value of solubility product (Ksp) of Ba(OH)2isa)4.0 × 10–6b)5.0 × 10–6c)3.3 × 10–7d)5.0 × 10–7Correct answer is option 'D'. Can you explain this answer?.
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