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You are given Avogadro number of "X" atoms. if half the atom of X transfers one electron to other half of X atom,409 KJ must be added. If these x- ions are subsequently converted to x+ , an addition 733KJ must be added . calculate ionisation potential and electron affinity of x in electron volt.(1 ev=1.602×10^-19 J)?
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You are given Avogadro number of "X" atoms. if half the atom of X tran...
On solving we get,
a+b = 15.194
Therefore, a or IE = 11.835 eV
b or EA = 3.358 eV
This question is part of UPSC exam. View all JEE courses
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You are given Avogadro number of "X" atoms. if half the atom of X tran...
Given information:
- Avogadro number of "X" atoms
- Half of the X atoms transfer one electron to the other half of X atoms, requiring 409 KJ of energy
- The resulting X- ions are converted to X atoms with the addition of 733 KJ of energy
Calculating the ionization potential:
Ionization potential is the energy required to remove an electron from an atom or ion in its ground state. In this case, half of the X atoms transfer one electron to the other half, suggesting that the energy required is for ionizing one electron from one X atom.
The energy required to ionize one electron can be calculated using the equation: ΔE = -IP (ionization potential) * e, where ΔE is the energy change and e is the elementary charge (1.602 × 10^-19 C).
Given that 409 KJ (409,000 J) of energy is required, we can rearrange the equation to solve for the ionization potential:
-IP * e = 409,000 J
IP = -409,000 J / e
Converting the ionization potential to electron volts (eV):
1 eV = 1.602 × 10^-19 J
IP (eV) = IP (J) / (1.602 × 10^-19 J/eV)
Calculating the electron affinity:
Electron affinity is the energy change when an electron is added to a neutral atom to form a negative ion. In this case, X- ions are converted back to X atoms with the addition of 733 KJ of energy. This implies that the energy change is for converting one X- ion to one X atom.
Using a similar approach as for ionization potential, we can calculate the electron affinity:
ΔE = -EA (electron affinity) * e
-733,000 J = -EA (J) * e
Converting the electron affinity to electron volts (eV):
EA (eV) = EA (J) / (1.602 × 10^-19 J/eV)
Calculations:
-IP = -409,000 J / e
IP (eV) = IP (J) / (1.602 × 10^-19 J/eV)
-EA = -733,000 J / e
EA (eV) = EA (J) / (1.602 × 10^-19 J/eV)
Results:
The ionization potential of X in electron volts is calculated as IP (eV), and the electron affinity of X in electron volts is calculated as EA (eV).
- Avogadro number of "X" atoms
- Half of the X atoms transfer one electron to the other half of X atoms, requiring 409 KJ of energy
- The resulting X- ions are converted to X atoms with the addition of 733 KJ of energy
Calculating the ionization potential:
Ionization potential is the energy required to remove an electron from an atom or ion in its ground state. In this case, half of the X atoms transfer one electron to the other half, suggesting that the energy required is for ionizing one electron from one X atom.
The energy required to ionize one electron can be calculated using the equation: ΔE = -IP (ionization potential) * e, where ΔE is the energy change and e is the elementary charge (1.602 × 10^-19 C).
Given that 409 KJ (409,000 J) of energy is required, we can rearrange the equation to solve for the ionization potential:
-IP * e = 409,000 J
IP = -409,000 J / e
Converting the ionization potential to electron volts (eV):
1 eV = 1.602 × 10^-19 J
IP (eV) = IP (J) / (1.602 × 10^-19 J/eV)
Calculating the electron affinity:
Electron affinity is the energy change when an electron is added to a neutral atom to form a negative ion. In this case, X- ions are converted back to X atoms with the addition of 733 KJ of energy. This implies that the energy change is for converting one X- ion to one X atom.
Using a similar approach as for ionization potential, we can calculate the electron affinity:
ΔE = -EA (electron affinity) * e
-733,000 J = -EA (J) * e
Converting the electron affinity to electron volts (eV):
EA (eV) = EA (J) / (1.602 × 10^-19 J/eV)
Calculations:
-IP = -409,000 J / e
IP (eV) = IP (J) / (1.602 × 10^-19 J/eV)
-EA = -733,000 J / e
EA (eV) = EA (J) / (1.602 × 10^-19 J/eV)
Results:
The ionization potential of X in electron volts is calculated as IP (eV), and the electron affinity of X in electron volts is calculated as EA (eV).
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You are given Avogadro number of "X" atoms. if half the atom of X transfers one electron to other half of X atom,409 KJ must be added. If these x- ions are subsequently converted to x+ , an addition 733KJ must be added . calculate ionisation potential and electron affinity of x in electron volt.(1 ev=1.602×10^-19 J)?
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You are given Avogadro number of "X" atoms. if half the atom of X transfers one electron to other half of X atom,409 KJ must be added. If these x- ions are subsequently converted to x+ , an addition 733KJ must be added . calculate ionisation potential and electron affinity of x in electron volt.(1 ev=1.602×10^-19 J)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about You are given Avogadro number of "X" atoms. if half the atom of X transfers one electron to other half of X atom,409 KJ must be added. If these x- ions are subsequently converted to x+ , an addition 733KJ must be added . calculate ionisation potential and electron affinity of x in electron volt.(1 ev=1.602×10^-19 J)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for You are given Avogadro number of "X" atoms. if half the atom of X transfers one electron to other half of X atom,409 KJ must be added. If these x- ions are subsequently converted to x+ , an addition 733KJ must be added . calculate ionisation potential and electron affinity of x in electron volt.(1 ev=1.602×10^-19 J)?.
You are given Avogadro number of "X" atoms. if half the atom of X transfers one electron to other half of X atom,409 KJ must be added. If these x- ions are subsequently converted to x+ , an addition 733KJ must be added . calculate ionisation potential and electron affinity of x in electron volt.(1 ev=1.602×10^-19 J)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about You are given Avogadro number of "X" atoms. if half the atom of X transfers one electron to other half of X atom,409 KJ must be added. If these x- ions are subsequently converted to x+ , an addition 733KJ must be added . calculate ionisation potential and electron affinity of x in electron volt.(1 ev=1.602×10^-19 J)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for You are given Avogadro number of "X" atoms. if half the atom of X transfers one electron to other half of X atom,409 KJ must be added. If these x- ions are subsequently converted to x+ , an addition 733KJ must be added . calculate ionisation potential and electron affinity of x in electron volt.(1 ev=1.602×10^-19 J)?.
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