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Evaluate: 
  • a)
    1/2
  • b)
    1/4
  • c)
    1
  • d)
    1/8
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Evaluate: a)1/2b)1/4c)1d)1/8Correct answer is option 'B'. Can you expl...
Let I = ∫(0 to pi/2)x3 sin(tan−1x4)/(1+x8)dx
Put tan−1 x4 = t
4x3/(1+x8)dx = dt
⇒x3dx/(1+x8) = dt/4
Now, I = 1/4∫sin t dt
=−[1/4 cos t]0 to pi/2 + c
= -1/4[cos(0) - cos(pi/2)] +c
= 1/4[-cos(pi/2) + cos(0)] +c
= ¼[-0+1]
= 1/4 
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Most Upvoted Answer
Evaluate: a)1/2b)1/4c)1d)1/8Correct answer is option 'B'. Can you expl...
This is maths questions I can explain it but you know it is not possible here because this app is not allow to take photo but try it ok let tan inverce 4x =t diff both side wrt x 4x³/1+x⁴ Ka square
x cube / 1+ x8 =dt/4 I = £ 0 se pie by 2 (because when x= 0 t = pie by 2and x = infinity then t = 0 )
I = 1/4 £ 0 se pie by 2 sin t l = 1/4 (- cos t limit 0 se pie by 2 )l = 1/4 ( - cos pie by 2 + cos 0) l = 1/4 ( 0+ 1) l= 1/4 × 1l= 1/4
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Community Answer
Evaluate: a)1/2b)1/4c)1d)1/8Correct answer is option 'B'. Can you expl...
Let I = ∫(0 to pi/2)x3 sin(tan−1x4)/(1+x8)dx
Put tan−1 x4 = t
4x3/(1+x8)dx = dt
⇒x3dx/(1+x8) = dt/4
Now, I = 1/4∫sin t dt
=−[1/4 cos t]0 to pi/2 + c
= -1/4[cos(0) - cos(pi/2)] +c
= 1/4[-cos(pi/2) + cos(0)] +c
= ¼[-0+1]
= 1/4 
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Evaluate: a)1/2b)1/4c)1d)1/8Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Evaluate: a)1/2b)1/4c)1d)1/8Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Evaluate: a)1/2b)1/4c)1d)1/8Correct answer is option 'B'. Can you explain this answer?.
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