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For any three positive real numbers a,b and c, 9(25a^2+b^2) + 25(c^2-3ac) = 15(3a + c). then (1) b,c and a are in GP (2) b,c and a are in AP (3) a,b and c are in AP (4) a,b and c are in GP? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared
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For any three positive real numbers a,b and c, 9(25a^2+b^2) + 25(c^2-3ac) = 15(3a + c). then (1) b,c and a are in GP (2) b,c and a are in AP (3) a,b and c are in AP (4) a,b and c are in GP?, a detailed solution for For any three positive real numbers a,b and c, 9(25a^2+b^2) + 25(c^2-3ac) = 15(3a + c). then (1) b,c and a are in GP (2) b,c and a are in AP (3) a,b and c are in AP (4) a,b and c are in GP? has been provided alongside types of For any three positive real numbers a,b and c, 9(25a^2+b^2) + 25(c^2-3ac) = 15(3a + c). then (1) b,c and a are in GP (2) b,c and a are in AP (3) a,b and c are in AP (4) a,b and c are in GP? theory, EduRev gives you an
ample number of questions to practice For any three positive real numbers a,b and c, 9(25a^2+b^2) + 25(c^2-3ac) = 15(3a + c). then (1) b,c and a are in GP (2) b,c and a are in AP (3) a,b and c are in AP (4) a,b and c are in GP? tests, examples and also practice JEE tests.