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If x is equal to one Y is equal to 6 is a solution of the equation 8 x minus A Y a square is equal to zero find the value of a?
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If x is equal to one Y is equal to 6 is a solution of the equation 8 x...
Since, x = 1 and y = 6 is a solution of the equation
8x - ay + a^2 = 0,
the values will satisfy the equation.

So, (8 x 1) - (a x 6) + a^2 = 0

⇒ a^2 - 6a + 8 = 0

⇒ a^2- (4 + 2)a + 8 = 0

⇒a^2 - 4a - 2a + 8 = 0

⇒ a(a - 4) - 2(a - 4) = 0

⇒ (a - 4)(a - 2) = 0

∴ a - 4 = 0 & a - 2 = 0

⇒ a = 4 & a = 2

∴ the required values of a are 4 and 2.
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If x is equal to one Y is equal to 6 is a solution of the equation 8 x minus A Y a square is equal to zero find the value of a?
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