2016 CBSE Class 9 Geometry Portion Answer:

Question:
Solve the following questions from the geometry portion of the 2016 CBSE Class 9 paper.

Answer:

1. Question:
In the given figure, PQ is a chord of length 8 cm of a circle of radius 5 cm. The tangents at P and Q intersect at a point T. Find the length of TP.

Solution:
Given that the radius of the circle is 5 cm and the chord PQ is 8 cm. We need to find the length of TP.

Explanation:
- In a circle, if two tangents are drawn from an external point, they are equal in length.
- So, TP = TQ

Using the above information, we can solve the problem.

2. Question:
In the given figure, O is the center of the circle and AB is a chord. If ∠AOB = 100°, find the value of ∠ACB.

Solution:
Given that ∠AOB = 100°. We need to find the value of ∠ACB.

Explanation:
- In a circle, the angle subtended by an arc at the center is twice the angle subtended by it at any point on the remaining part of the circle.
- So, ∠ACB = ∠AOB/2

Using the above information, we can solve the problem.

3. Question:
In the given figure, O is the center of the circle and AB is a chord. If ∠AOB = 130°, find the value of ∠BAC.

Solution:
Given that ∠AOB = 130°. We need to find the value of ∠BAC.

Explanation:
- In a circle, the angle subtended by an arc at the center is twice the angle subtended by it at any point on the remaining part of the circle.
- So, ∠BAC = (180° - ∠AOB)/2

Using the above information, we can solve the problem.

4. Question:
In the given figure, AB and CD are two diameters of the circle with center O. If ∠ACD = 60°, find the value of ∠BAD.

Solution:
Given that ∠ACD = 60°. We need to find the value of ∠BAD.

Explanation:
- In a circle, if a quadrilateral is inscribed in it, then the opposite angles of the quadrilateral are supplementary.
- So, ∠BAD = 180° - ∠ACD

Using the above information, we can solve the problem.

These were the solutions to the geometry portion of the 2016 CBSE Class 9 paper.

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