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A coil of 100 turns is pulled in 0.04 sec. between the poles of a magnet, if its flux changes from 40 x 10-6 Wb per turn to 10-5 Wb per turn, then the average emf induced in the coil is​
  • a)
    0.75V
  • b)
    7.5V
  • c)
    0.0075V
  • d)
    0.075V
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A coil of 100 turns is pulled in 0.04 sec. between the poles of a magn...
Emf = - N(∆magnetic flux)/∆t
N=100turns
∆magnetic flux= -30×10-6Wb
∆t = 0.04sec
Emf = -(100turns)(-30×10-6)/(0.04sec)
Emf = 0.075V
 
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Most Upvoted Answer
A coil of 100 turns is pulled in 0.04 sec. between the poles of a magn...
Given:
Number of turns, N = 100
Time taken, t = 0.04 sec
Initial flux per turn, Φ1 = 40 x 10^-6 Wb
Final flux per turn, Φ2 = 10^-5 Wb

To find: Average emf induced in the coil

Formula used:
The average emf induced in a coil is given by
E = ΔΦ/Δt
where ΔΦ is the change in magnetic flux and Δt is the time taken for the change.

Calculation:
Change in magnetic flux, ΔΦ = Φ2 - Φ1
= (10^-5 - 40 x 10^-6) Wb
= 6 x 10^-6 Wb

Time taken for the change, Δt = t/N
= 0.04/100 sec
= 4 x 10^-4 sec

Average emf induced in the coil, E = ΔΦ/Δt
= (6 x 10^-6)/(4 x 10^-4) V
= 0.075 V

Therefore, the average emf induced in the coil is 0.075 V, which is option D.
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Community Answer
A coil of 100 turns is pulled in 0.04 sec. between the poles of a magn...
Emf = - N(∆magnetic flux)/∆t
N=100turns
∆magnetic flux= -30×10-6Wb
∆t = 0.04sec
Emf = -(100turns)(-30×10-6)/(0.04sec)
Emf = 0.075V
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A coil of 100 turns is pulled in 0.04 sec. between the poles of a magnet, if its flux changes from 40 x 10-6Wb per turn to 10-5Wb per turn, then the average emf induced in the coil is​a)0.75Vb)7.5Vc)0.0075Vd)0.075VCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A coil of 100 turns is pulled in 0.04 sec. between the poles of a magnet, if its flux changes from 40 x 10-6Wb per turn to 10-5Wb per turn, then the average emf induced in the coil is​a)0.75Vb)7.5Vc)0.0075Vd)0.075VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil of 100 turns is pulled in 0.04 sec. between the poles of a magnet, if its flux changes from 40 x 10-6Wb per turn to 10-5Wb per turn, then the average emf induced in the coil is​a)0.75Vb)7.5Vc)0.0075Vd)0.075VCorrect answer is option 'D'. Can you explain this answer?.
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