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calcium sulphate in hard water dissociated in calcium ions and sulphate ions. calculate the no. of ions present in water excluding ions of water,when 68gm of calcium sulphate dissolved in water.
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calcium sulphate in hard water dissociated in calcium ions and sulpha...
Avagadro's law states that 1 mole of any substance has 6.022×10²³ molecules or atoms. That is 6.022×10²³ mol⁻¹

Find the mole of 68 g of calcium sulphate (CaSO4)

moles = mass / molar mass

molar mass of CaSO4 is 136

mole = 68/136
= 0.5 moles

Therefore the number of molecules in CaSO4 is:

0.5 moles × 6.022×10²³ mol⁻¹ = 3.0115 × 10²³

Therefore there are 3.0115 ×10²³ molecules of CaSO4 in the solution.

When 1 molecule of CaSO4 ions dissociate, 2 ions of Ca ions and SO4 ions are formed.

That means 3.0115 ×10²³ molecules will form

= 3.0115 ×10²³ molecules x 2

= 6.023 ×10²³ ions in the solution
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calcium sulphate in hard water dissociated in calcium ions and sulphate ions. calculate the no. of ions present in water excluding ions of water,when 68gm of calcium sulphate dissolved in water.
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