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calcium sulphate in hard water remains dissociated in calcium and sulphate ions calculate the no. of ions present in water excluding ions of water,when 68gm of calcium sulphate dissolves in water.
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calcium sulphate in hard water remains dissociated in calcium and sulp...
Avagadro's law states that 1 mole of any substance has 6.022 * 10^23 molecules or atoms. That is 6.022 * 10^23 mol^-1.

Find the mole of 68 g of calcium sulphate (CaSO4)

moles = mass / molar mass

molar mass of CaSO4 is 136

mole = 68/136

= 0.5 moles

Therefore the number of molecules in CaSO4 is:

0.5 moles  * 6.022 * 10^23 mol^-1  =  3.0115 * 10^23

Therefore there are 3.0115 * 10^23  molecules of CaSO4 in the solution.

When 1 molecule of CaSO4 ions dissociate, 2 ions of Ca ions and SO4 ions are formed.

That means 3.0115 * 10^23  molecules will form.
  
= 3.0115 * 10^23  molecules * 2
        
=  6.023 * 10^23 ions in the solution.
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calcium sulphate in hard water remains dissociated in calcium and sulphate ions calculate the no. of ions present in water excluding ions of water,when 68gm of calcium sulphate dissolves in water.
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