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A body of mass 60 kg is dragged with just enough force to start moving on a rough surface with coefficients of static and kinetic frictions 0.5 and 0.4 respectively. On applying the same force, what is the acceleration?
- a)0.98 m/s2
- b)9.8 m/s2
- c)0.54 m/s2
- d)5.292 m/s2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A body of mass 60 kg is dragged with just enough force to start moving...
maximum static friction that can act on the body is Umg = 0.5*60*9.8 = 294 N
now since the force is just above 300 N, the body will translate and the type of friction now will be kinetic instead of static. Hence the net acceleration is 294-0.4*60*9.8/60 = 0.98 m/s^2 Ans.
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Community Answer
A body of mass 60 kg is dragged with just enough force to start moving...
To determine the acceleration of a body being dragged on a rough surface, we need to consider the forces acting on the body. In this case, we have the force of friction and the applied force.
Frictional Force:
The frictional force can be calculated using the equation:
frictional force = coefficient of friction * normal force
Normal Force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the body is being dragged, so the normal force is equal to the weight of the body, which can be calculated as:
normal force = mass * gravitational acceleration
Constant Applied Force:
The applied force is the force that is being used to drag the body. This force is equal to the force of friction required to start the motion.
Coefficient of Static Friction:
The coefficient of static friction (μs) represents the amount of friction between two objects when they are not moving relative to each other. In this case, the applied force is just enough to overcome the static friction and start the motion.
Coefficient of Kinetic Friction:
The coefficient of kinetic friction (μk) represents the amount of friction between two objects when they are in motion relative to each other. Once the body starts moving, the coefficient of kinetic friction comes into play.
Acceleration:
The acceleration of the body can be calculated using Newton's second law of motion:
force = mass * acceleration
Now, let's calculate the acceleration using the given information:
1. Calculate the normal force:
normal force = mass * gravitational acceleration
normal force = 60 kg * 9.8 m/s^2
normal force = 588 N
2. Calculate the force of friction:
frictional force = coefficient of static friction * normal force
frictional force = 0.5 * 588 N
frictional force = 294 N
3. Calculate the acceleration:
force = mass * acceleration
force = frictional force
294 N = 60 kg * acceleration
acceleration = 294 N / 60 kg
acceleration = 4.9 m/s^2
Therefore, the acceleration of the body when the same force is applied is 4.9 m/s^2.
Frictional Force:
The frictional force can be calculated using the equation:
frictional force = coefficient of friction * normal force
Normal Force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the body is being dragged, so the normal force is equal to the weight of the body, which can be calculated as:
normal force = mass * gravitational acceleration
Constant Applied Force:
The applied force is the force that is being used to drag the body. This force is equal to the force of friction required to start the motion.
Coefficient of Static Friction:
The coefficient of static friction (μs) represents the amount of friction between two objects when they are not moving relative to each other. In this case, the applied force is just enough to overcome the static friction and start the motion.
Coefficient of Kinetic Friction:
The coefficient of kinetic friction (μk) represents the amount of friction between two objects when they are in motion relative to each other. Once the body starts moving, the coefficient of kinetic friction comes into play.
Acceleration:
The acceleration of the body can be calculated using Newton's second law of motion:
force = mass * acceleration
Now, let's calculate the acceleration using the given information:
1. Calculate the normal force:
normal force = mass * gravitational acceleration
normal force = 60 kg * 9.8 m/s^2
normal force = 588 N
2. Calculate the force of friction:
frictional force = coefficient of static friction * normal force
frictional force = 0.5 * 588 N
frictional force = 294 N
3. Calculate the acceleration:
force = mass * acceleration
force = frictional force
294 N = 60 kg * acceleration
acceleration = 294 N / 60 kg
acceleration = 4.9 m/s^2
Therefore, the acceleration of the body when the same force is applied is 4.9 m/s^2.
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A body of mass 60 kg is dragged with just enough force to start moving on a rough surface with coefficients of static and kinetic frictions 0.5 and 0.4 respectively. On applying the same force, what is the acceleration? a)0.98 m/s2b)9.8 m/s2c)0.54 m/s2d)5.292 m/s2Correct answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body of mass 60 kg is dragged with just enough force to start moving on a rough surface with coefficients of static and kinetic frictions 0.5 and 0.4 respectively. On applying the same force, what is the acceleration? a)0.98 m/s2b)9.8 m/s2c)0.54 m/s2d)5.292 m/s2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 60 kg is dragged with just enough force to start moving on a rough surface with coefficients of static and kinetic frictions 0.5 and 0.4 respectively. On applying the same force, what is the acceleration? a)0.98 m/s2b)9.8 m/s2c)0.54 m/s2d)5.292 m/s2Correct answer is option 'A'. Can you explain this answer?.
A body of mass 60 kg is dragged with just enough force to start moving on a rough surface with coefficients of static and kinetic frictions 0.5 and 0.4 respectively. On applying the same force, what is the acceleration? a)0.98 m/s2b)9.8 m/s2c)0.54 m/s2d)5.292 m/s2Correct answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A body of mass 60 kg is dragged with just enough force to start moving on a rough surface with coefficients of static and kinetic frictions 0.5 and 0.4 respectively. On applying the same force, what is the acceleration? a)0.98 m/s2b)9.8 m/s2c)0.54 m/s2d)5.292 m/s2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 60 kg is dragged with just enough force to start moving on a rough surface with coefficients of static and kinetic frictions 0.5 and 0.4 respectively. On applying the same force, what is the acceleration? a)0.98 m/s2b)9.8 m/s2c)0.54 m/s2d)5.292 m/s2Correct answer is option 'A'. Can you explain this answer?.
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