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A man can throw a stone with initial speed of 10m/s.find the maximum horizontal distance to which he can throw the stone in a room of height is 2m?
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A man can throw a stone with initial speed of 10m/s.find the maximum h...
Maximum horizontal distance a stone can be thrown in a room of height 2m


Assumptions



  • The room is a closed box with a flat roof at a height of 2m.

  • There is no air resistance.

  • Gravity is acting vertically downwards with a constant acceleration of 9.8m/s^2.

  • The stone is thrown horizontally.

  • The stone is thrown from the ground.



Solution


When the stone is thrown horizontally, it has an initial horizontal velocity of 10m/s and an initial vertical velocity of 0m/s. The stone will continue to move horizontally at a constant velocity, while its vertical velocity will be affected by gravity.


Using the equation of motion, we can calculate the time taken for the stone to hit the roof of the room:


2 = (1/2)gt^2


where g is the acceleration due to gravity and t is the time taken for the stone to hit the roof.


On solving the above equation, we get t = sqrt(4/9.8) = 0.90s.


The horizontal distance travelled by the stone in 0.90s can be calculated using the formula:


d = vt


where v is the initial horizontal velocity of the stone and t is the time taken for the stone to hit the roof.


Therefore, d = 10 x 0.90 = 9m.


Conclusion


The maximum horizontal distance that a stone can be thrown in a room of height 2m is 9m.
Community Answer
A man can throw a stone with initial speed of 10m/s.find the maximum h...
Given: u=10m/s maximum height(H)=2m g=10m/s^2
H=(u*u*sin^2)/2g
2=(10*10*sin^2)/20
sin^2 =1/2.5
let...sin =sqrt (1/2)
sin = sin45
maximum distance (R)=(u*u*sin2 )/g
R=(10*10*sin2(45))/g
R=100*sin(90)/10
R=10m
hence he can throw the stone for 10 m in 2 m height room.
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A man can throw a stone with initial speed of 10m/s.find the maximum horizontal distance to which he can throw the stone in a room of height is 2m?
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