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A cricketer can throw a ball to a maximum horizontal distance of 100 m. The speed with which he throws the ball is (to the nearest integer)
- a)30 ms⁻1
- b)42 ms⁻1
- c)32 ms⁻1
- d)35 ms⁻1
Correct answer is option 'C'. Can you explain this answer?
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A cricketer can throw a ball to a maximum horizontal distance of 100 m...
Given, the maximum horizontal distance that a cricketer can throw the ball, d = 100 m.
We know that the horizontal range of a projectile can be given by the formula:
d = (v^2/g) x sin(2θ)
where,
v = speed of the projectile
g = acceleration due to gravity (9.8 m/s^2)
θ = angle of projection
Since the angle of projection is not given, we can assume it to be 45 degrees (which gives the maximum range for a given velocity).
Substituting the values in the formula, we get:
100 = (v^2/9.8) x sin(90)
100 x 9.8 = v^2
v = √(980)
v ≈ 31.3 m/s
Rounding off to the nearest integer, we get the speed with which the cricketer throws the ball as 32 m/s, which is option C.
We know that the horizontal range of a projectile can be given by the formula:
d = (v^2/g) x sin(2θ)
where,
v = speed of the projectile
g = acceleration due to gravity (9.8 m/s^2)
θ = angle of projection
Since the angle of projection is not given, we can assume it to be 45 degrees (which gives the maximum range for a given velocity).
Substituting the values in the formula, we get:
100 = (v^2/9.8) x sin(90)
100 x 9.8 = v^2
v = √(980)
v ≈ 31.3 m/s
Rounding off to the nearest integer, we get the speed with which the cricketer throws the ball as 32 m/s, which is option C.
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A cricketer can throw a ball to a maximum horizontal distance of 100 m. The speed with which he throws the ball is (to the nearest integer)a)30 ms1b)42 ms1c)32 ms1d)35 ms1Correct answer is option 'C'. Can you explain this answer?
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