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Two blocks are in contact on a frictionless table one has made m and the other 2m. A force f is applied on 2m. Now the same force is applied from the right on m. In the two cases respectively, the ratio of force in contact between the two blocks will be -?
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Two blocks are in contact on a frictionless table one has made m and t...
1:2. On 2m N = f(m/m+2m)=f/3 On m - N=f (2m/m+2m)=2f/3ratio=(f/3)/(2f/3)=1/2=1:2. here (m or 2m)/m+2m indicates accelration.
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Two blocks are in contact on a frictionless table one has made m and t...
Friction between two blocks of masses m and 2m
When two blocks are in contact on a frictionless table, the force of friction between them is determined by the normal force and the coefficient of friction. However, in this case, the table is frictionless, so there is no force of friction between the blocks.
Case 1: Force applied on 2m block
When a force f is applied on the 2m block, the force of contact between the two blocks can be determined using Newton's third law of motion. According to this law, for every action, there is an equal and opposite reaction. So, the force of contact between the blocks will be equal to the force applied on the 2m block, which is f.
Case 2: Force applied on m block
Now, let's consider the scenario where the same force f is applied from the right on the m block. In this case, we need to analyze the forces acting on the system.
- The applied force f will cause the m block to accelerate to the right.
- Due to the absence of friction, there will be no horizontal force acting on the 2m block.
- As a result, the 2m block will remain at rest.
Since the force of contact between the two blocks is determined by the acceleration of the m block, which is f/m, the ratio of the force in contact between the two blocks in this case will be f/m.
Ratio of forces
To find the ratio of the forces in contact between the two blocks in the two cases, we can divide the force in Case 2 by the force in Case 1.
Ratio = (force in Case 2) / (force in Case 1)
Ratio = (f/m) / f
Ratio = 1/m
Therefore, the ratio of the force in contact between the two blocks will be 1/m.
When two blocks are in contact on a frictionless table, the force of friction between them is determined by the normal force and the coefficient of friction. However, in this case, the table is frictionless, so there is no force of friction between the blocks.
Case 1: Force applied on 2m block
When a force f is applied on the 2m block, the force of contact between the two blocks can be determined using Newton's third law of motion. According to this law, for every action, there is an equal and opposite reaction. So, the force of contact between the blocks will be equal to the force applied on the 2m block, which is f.
Case 2: Force applied on m block
Now, let's consider the scenario where the same force f is applied from the right on the m block. In this case, we need to analyze the forces acting on the system.
- The applied force f will cause the m block to accelerate to the right.
- Due to the absence of friction, there will be no horizontal force acting on the 2m block.
- As a result, the 2m block will remain at rest.
Since the force of contact between the two blocks is determined by the acceleration of the m block, which is f/m, the ratio of the force in contact between the two blocks in this case will be f/m.
Ratio of forces
To find the ratio of the forces in contact between the two blocks in the two cases, we can divide the force in Case 2 by the force in Case 1.
Ratio = (force in Case 2) / (force in Case 1)
Ratio = (f/m) / f
Ratio = 1/m
Therefore, the ratio of the force in contact between the two blocks will be 1/m.
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Two blocks are in contact on a frictionless table one has made m and the other 2m. A force f is applied on 2m. Now the same force is applied from the right on m. In the two cases respectively, the ratio of force in contact between the two blocks will be -?
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Two blocks are in contact on a frictionless table one has made m and the other 2m. A force f is applied on 2m. Now the same force is applied from the right on m. In the two cases respectively, the ratio of force in contact between the two blocks will be -? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two blocks are in contact on a frictionless table one has made m and the other 2m. A force f is applied on 2m. Now the same force is applied from the right on m. In the two cases respectively, the ratio of force in contact between the two blocks will be -? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two blocks are in contact on a frictionless table one has made m and the other 2m. A force f is applied on 2m. Now the same force is applied from the right on m. In the two cases respectively, the ratio of force in contact between the two blocks will be -?.
Two blocks are in contact on a frictionless table one has made m and the other 2m. A force f is applied on 2m. Now the same force is applied from the right on m. In the two cases respectively, the ratio of force in contact between the two blocks will be -? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two blocks are in contact on a frictionless table one has made m and the other 2m. A force f is applied on 2m. Now the same force is applied from the right on m. In the two cases respectively, the ratio of force in contact between the two blocks will be -? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two blocks are in contact on a frictionless table one has made m and the other 2m. A force f is applied on 2m. Now the same force is applied from the right on m. In the two cases respectively, the ratio of force in contact between the two blocks will be -?.
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