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The solution of the differential equation 
is :
is :- a)a log sec by + beax = c
- b)a log (sec by + tan by) = beax + c
- c)a log (sec by + tan by) + beax = c
- d)a log sec by + beax + c
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The solution of the differential equation is :a)a log sec by + beax = ...
dy/dx = eax cos by
∫dy/cos by = ∫eax dx
∫sec by dy = ∫eax dx
= (log| sec by + tan by|)/b = eax /a + c
= a(log| sec by + tan by|) = beax + c
∫dy/cos by = ∫eax dx
∫sec by dy = ∫eax dx
= (log| sec by + tan by|)/b = eax /a + c
= a(log| sec by + tan by|) = beax + c
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The solution of the differential equation is :a)a log sec by + beax = ...
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The solution of the differential equation is :a)a log sec by + beax = ...
dy/dx = eax cos by
∫dy/cos by = ∫eax dx
∫sec by dy = ∫eax dx
= (log| sec by + tan by|)/b = eax /a + c
= a(log| sec by + tan by|) = beax + c
∫dy/cos by = ∫eax dx
∫sec by dy = ∫eax dx
= (log| sec by + tan by|)/b = eax /a + c
= a(log| sec by + tan by|) = beax + c
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The solution of the differential equation is :a)a log sec by + beax = cb)a log (sec by + tan by) =beax+ cc)a log (sec by + tan by) +beax = cd)a log sec by + beax+cCorrect answer is option 'B'. Can you explain this answer?
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The solution of the differential equation is :a)a log sec by + beax = cb)a log (sec by + tan by) =beax+ cc)a log (sec by + tan by) +beax = cd)a log sec by + beax+cCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The solution of the differential equation is :a)a log sec by + beax = cb)a log (sec by + tan by) =beax+ cc)a log (sec by + tan by) +beax = cd)a log sec by + beax+cCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The solution of the differential equation is :a)a log sec by + beax = cb)a log (sec by + tan by) =beax+ cc)a log (sec by + tan by) +beax = cd)a log sec by + beax+cCorrect answer is option 'B'. Can you explain this answer?.
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