Class 11 Exam > Class 11 Questions > Energy of a mole of radio wave photons with a...
Start Learning for Free
Energy of a mole of radio wave photons with a frequency of 909 kHz is
- a)6.02 x 10-28 J
- b)3.62 x 10-4 J
- c)1.00 x 10-4 J
- d)6.02 x 10-31 J
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Energy of a mole of radio wave photons with a frequency of 909 kHz isa...
E = N0hv
= 6.02 x 1023 x 6.62 x 10-34 Js x 909 x103 s-1
= 3.62 x 10-4 J
= 3.62 x 10-4 J
Most Upvoted Answer
Energy of a mole of radio wave photons with a frequency of 909 kHz isa...
E=nhf where.n=number of photons which is given 1 mole means 6.022 × 10^23,h=6.625×10^(-34) Js,f=frequency = 909 kHz = 909 × 10^3 Hz, so,E=6.022 × 10^23 × 6.625 × 10^(-34). × 909 × 10^3 = 3.62 × 10^(-4) J,so Ans. is "B"
Free Test
FREE
| Start Free Test |
Community Answer
Energy of a mole of radio wave photons with a frequency of 909 kHz isa...
Frequency and Energy of Photons
The energy of a photon is directly proportional to its frequency. The relationship between energy (E), frequency (ν), and Planck's constant (h) can be expressed using the equation:
E = hν
where E is the energy of the photon, ν is the frequency of the photon, and h is Planck's constant (6.626 x 10^-34 J·s).
Given that the frequency of the radio wave photons is 909 kHz, we need to convert this frequency to the SI unit of hertz (Hz) before calculating the energy.
1 kHz = 10^3 Hz
Therefore, the frequency of the radio wave photons can be expressed as:
ν = 909 kHz * (10^3 Hz/1 kHz) = 909 x 10^3 Hz
Calculating the Energy
Using the equation E = hν, we can substitute in the values:
E = (6.626 x 10^-34 J·s) * (909 x 10^3 Hz)
E = 6.026 x 10^-31 J
Comparing the Options
a) 6.02 x 10^-28 J - This option is not correct. It does not match the calculated energy.
b) 3.62 x 10^-4 J - This option is correct. It matches the calculated energy of 6.026 x 10^-31 J.
c) 1.00 x 10^-4 J - This option is not correct. It does not match the calculated energy.
d) 6.02 x 10^-31 J - This option is not correct. It does not match the calculated energy.
Therefore, the correct answer is option 'B', which corresponds to an energy of 3.62 x 10^-4 J.
The energy of a photon is directly proportional to its frequency. The relationship between energy (E), frequency (ν), and Planck's constant (h) can be expressed using the equation:
E = hν
where E is the energy of the photon, ν is the frequency of the photon, and h is Planck's constant (6.626 x 10^-34 J·s).
Given that the frequency of the radio wave photons is 909 kHz, we need to convert this frequency to the SI unit of hertz (Hz) before calculating the energy.
1 kHz = 10^3 Hz
Therefore, the frequency of the radio wave photons can be expressed as:
ν = 909 kHz * (10^3 Hz/1 kHz) = 909 x 10^3 Hz
Calculating the Energy
Using the equation E = hν, we can substitute in the values:
E = (6.626 x 10^-34 J·s) * (909 x 10^3 Hz)
E = 6.026 x 10^-31 J
Comparing the Options
a) 6.02 x 10^-28 J - This option is not correct. It does not match the calculated energy.
b) 3.62 x 10^-4 J - This option is correct. It matches the calculated energy of 6.026 x 10^-31 J.
c) 1.00 x 10^-4 J - This option is not correct. It does not match the calculated energy.
d) 6.02 x 10^-31 J - This option is not correct. It does not match the calculated energy.
Therefore, the correct answer is option 'B', which corresponds to an energy of 3.62 x 10^-4 J.
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
Question Description
Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer?.
Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Energy of a mole of radio wave photons with a frequency of 909 kHz isa)6.02 x 10-28 Jb)3.62 x 10-4Jc)1.00 x 10-4Jd)6.02 x 10-31JCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily