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Direction (Q. Nos. 16 and 17) This section contains a paragraph, each describing theory, experiments, data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).
Passage
Sulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in addition to this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.
Q.
Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively are
  • a)
    + 6 and + 7
  • b)
    + 6 and + 6
  • c)
    + 5 and + 6
  • d)
    + 5 and + 7
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Direction (Q. Nos. 16and 17) This section contains a paragraph, each d...
H2S2O7 has no peroxy bond while H2S2O8 has one peroxy bond.

 
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Direction (Q. Nos. 16and 17) This section contains a paragraph, each d...
H2S2O7 has no peroxy bond while H2S2O8 has one peroxy bond.

 
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Direction (Q. Nos. 16and 17) This section contains a paragraph, each d...
In H2S2O7.,let oxidation state of S be X.=2×1+2×X+7(-2)=0.=2+2X-14=0.2X-12=0.2X=12.X=6..in H2S2O8,let oxidation state of S be X.2×1+2×X+8(-2)=0.2+2X-16=0.2X-14=0.2X=14.X=7....but any elements oxidation state does not exceeds its group number.. as sulphur belongs to 6th group , its oxidation state will remain 6 in both of them...
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Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer?.
Solutions for Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Direction (Q. Nos. 16and 17) This section contains a paragraph, each describing theory, experiments,data, etc. Two questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).PassageSulphur and the rest of the elements of 16th group are less electronegative than oxygen. They can acquire ns2np6 by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds, in additionto this, atoms have vacant d-orbitals in their valence shell due to which electrons I can be promoted from the s- and p-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states. The oxidation states of elements never exceed +6.Q.Oxidation states of sulphur in H2S2O7 and H2S2O8 respectively area)+ 6 and + 7b)+ 6 and + 6c)+ 5 and + 6d)+ 5 and + 7Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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