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How many three letter codes can be formed by only vowels of English alphabets, given that repetition of letters is allowed?
  • a)
    125
  • b)
    5
  • c)
    25
  • d)
    5!
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
How many three letter codes can be formed by only vowels of English al...
A three letter word, to fill the 1st letter, we have 5 choices (a, e, i, o, u); to fill the 2nd letter, we again have 5 choices (a, e, i, o, u) as repeatation is allowed and at last to fill the 3rd letter, we again have 5 choices (a, e, i, o, u). So, combinations available to form a 3 letter code from vowels are 5 × 5 × 5 = 125.
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How many three letter codes can be formed by only vowels of English al...
Number of Three-Letter Codes with Repetition of Vowels

To determine the number of three-letter codes that can be formed using only vowels of the English alphabet, we need to consider the following:

Step 1: Identify the Vowels in the English Alphabet
The English alphabet consists of 26 letters, out of which five are vowels: A, E, I, O, and U. These are the letters we will be using to form the three-letter codes.

Step 2: Determine the Number of Options for Each Position
Since repetition of letters is allowed, we can choose any vowel for each position. Therefore, for each position, there are five options (A, E, I, O, or U).

Step 3: Multiply the Number of Options for Each Position
To find the total number of three-letter codes, we need to multiply the number of options for each position. Since there are three positions, we multiply 5 options by itself three times.

5 x 5 x 5 = 125

Therefore, the correct answer is option 'A', 125.

Explanation:
When forming three-letter codes using only vowels of the English alphabet, repetition is allowed. This means that each position can be filled with any vowel multiple times.

For the first position, there are five options: A, E, I, O, or U. Similarly, for the second and third positions, there are also five options each.

To find the total number of three-letter codes, we multiply the number of options for each position. Since there are three positions, we multiply 5 options by itself three times:

5 x 5 x 5 = 125

Therefore, there are 125 possible three-letter codes that can be formed using only vowels of the English alphabet when repetition is allowed.
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How many three letter codes can be formed by only vowels of English alphabets, given that repetition of letters is allowed?a)125b)5c)25d)5!Correct answer is option 'A'. Can you explain this answer?
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