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A bullet fired vertically up from the ground reaches a height 40m in its path from the ground. And it takes further 2 seconds to reach that point.the time for which body remains in in air is ?.the answer for this is 6seconds.?
Most Upvoted Answer
A bullet fired vertically up from the ground reaches a height 40m in i...
Understanding the problem:
A bullet is fired vertically up from the ground and reaches a height of 40m in its path. After reaching this point, it takes further 2 seconds to come back to the ground. We need to find out the total time for which the bullet remains in the air.
Solution:
To solve this problem, we need to consider the motion of the bullet in two parts:
1. The time it takes to reach the maximum height of 40m.
2. The time it takes to come back to the ground.
Calculating time to reach the maximum height:
To calculate the time taken by the bullet to reach the maximum height, we can use the formula:
v^2 - u^2 = 2as
where,
v = final velocity (0 m/s as the bullet reaches the maximum height)
u = initial velocity (unknown)
a = acceleration due to gravity (-9.8 m/s^2)
s = displacement (40m)
Substituting the values, we get:
0^2 - u^2 = 2(-9.8)(40)
u^2 = 2(-9.8)(40)
u = 39.2 m/s
Now, we can use the formula:
v = u + at
where,
v = final velocity (0 m/s as the bullet reaches the maximum height)
u = initial velocity (39.2 m/s)
a = acceleration due to gravity (-9.8 m/s^2)
t = time taken to reach the maximum height
Substituting the values, we get:
0 = 39.2 - 9.8t
t = 4 seconds
Calculating time to come back to the ground:
Since the bullet takes 2 seconds to come back to the ground, we can directly use this value.
Total time for which the bullet remains in the air:
The total time for which the bullet remains in the air is given by:
Total time = time to reach maximum height + time to come back to the ground
Total time = 4 + 2 = 6 seconds
Therefore, the bullet remains in the air for 6 seconds.
A bullet is fired vertically up from the ground and reaches a height of 40m in its path. After reaching this point, it takes further 2 seconds to come back to the ground. We need to find out the total time for which the bullet remains in the air.
Solution:
To solve this problem, we need to consider the motion of the bullet in two parts:
1. The time it takes to reach the maximum height of 40m.
2. The time it takes to come back to the ground.
Calculating time to reach the maximum height:
To calculate the time taken by the bullet to reach the maximum height, we can use the formula:
v^2 - u^2 = 2as
where,
v = final velocity (0 m/s as the bullet reaches the maximum height)
u = initial velocity (unknown)
a = acceleration due to gravity (-9.8 m/s^2)
s = displacement (40m)
Substituting the values, we get:
0^2 - u^2 = 2(-9.8)(40)
u^2 = 2(-9.8)(40)
u = 39.2 m/s
Now, we can use the formula:
v = u + at
where,
v = final velocity (0 m/s as the bullet reaches the maximum height)
u = initial velocity (39.2 m/s)
a = acceleration due to gravity (-9.8 m/s^2)
t = time taken to reach the maximum height
Substituting the values, we get:
0 = 39.2 - 9.8t
t = 4 seconds
Calculating time to come back to the ground:
Since the bullet takes 2 seconds to come back to the ground, we can directly use this value.
Total time for which the bullet remains in the air:
The total time for which the bullet remains in the air is given by:
Total time = time to reach maximum height + time to come back to the ground
Total time = 4 + 2 = 6 seconds
Therefore, the bullet remains in the air for 6 seconds.
Community Answer
A bullet fired vertically up from the ground reaches a height 40m in i...
40=1/2a(t+2)^2
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A bullet fired vertically up from the ground reaches a height 40m in its path from the ground. And it takes further 2 seconds to reach that point.the time for which body remains in in air is ?.the answer for this is 6seconds.?
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A bullet fired vertically up from the ground reaches a height 40m in its path from the ground. And it takes further 2 seconds to reach that point.the time for which body remains in in air is ?.the answer for this is 6seconds.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A bullet fired vertically up from the ground reaches a height 40m in its path from the ground. And it takes further 2 seconds to reach that point.the time for which body remains in in air is ?.the answer for this is 6seconds.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet fired vertically up from the ground reaches a height 40m in its path from the ground. And it takes further 2 seconds to reach that point.the time for which body remains in in air is ?.the answer for this is 6seconds.?.
A bullet fired vertically up from the ground reaches a height 40m in its path from the ground. And it takes further 2 seconds to reach that point.the time for which body remains in in air is ?.the answer for this is 6seconds.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A bullet fired vertically up from the ground reaches a height 40m in its path from the ground. And it takes further 2 seconds to reach that point.the time for which body remains in in air is ?.the answer for this is 6seconds.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bullet fired vertically up from the ground reaches a height 40m in its path from the ground. And it takes further 2 seconds to reach that point.the time for which body remains in in air is ?.the answer for this is 6seconds.?.
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