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Statement I
1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.

On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.
Statement II
Equilibrium constant, Kc = 1
  • a)
    Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement I
  • b)
    Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I
  • c)
    Statement I is correct but Statement II is incorrect
  • d)
    Statement II is incorrect but Statement II is correct
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mo...
Step 1: Analyze Statement I
Statement I says:
1 mole of A(g) and 1 mole of B(g) produce 0.5 mole of C(g) and 0.5 mole of D(g) at equilibrium.
This implies the reaction:
A(g) + B(g) ⇌ C(g) + D(g)
Initially:
  • Moles of A(g) = 1
  • Moles of B(g) = 1
At equilibrium, we have:
  • 0.5 moles of C(g)
  • 0.5 moles of D(g)
So, 0.5 moles ofA and 0.5 moles of B have reacted, meaning the reaction has gone halfway to completion.
Step 2: Determine the effect of doubling the initial moles
Now, if we take 2 moles each of A(g) and B(g), the reaction should still proceed in the same manner as before, and the dissociation (reaction extent) will also double.
So, instead of 0.5 moles of A and B reacting, 1 mole of AA and 1 mole of B will react. This means the percentage dissociation ofA and B doubles, which is in line with Statement I.
Step 3: Analyze Statement II
Statement II says that the equilibrium constant Kc​ = 1.
The equilibrium constant is given by the expression:
At equilibrium, if we have:
  • 0.5 moles of C and D
  • 0.5 moles of A and B remaining
Then, assuming the volume is constant and we can use molar concentrations directly, the equilibrium constant would be:

Thus, Statement II is correct: Kc​ = 1.
Conclusion
  • Statement I is correct because the percentage dissociation of A and B doubles when their initial amounts are doubled.
  • Statement II is also correct because the equilibrium constant Kc​ = 1.
However, Statement II does not explain Statement I. The relationship between initial moles and dissociation is a separate concept from the equilibrium constant value.
Therefore, the correct answer is: Answer: D
Statement II is correct, but Statement II does not explain Statement I.
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Community Answer
Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mo...
No answer . in option"D" it has given that both statements AS II
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Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer?
Question Description
Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Statement I 1 mole A(g) and 1 mole B(g)give 0.5 mole of C(g)and 0.5 mole D(g) at equilibrium.On taking 2 moles each of A(g)and B(g), percentage dissociation A(g)and B(g) is also doubled.Statement IIEquilibrium constant, Kc = 1a)Both Statement I and Statement II are correct and Statement II is the corect explanation of Statement Ib)Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement Ic)Statement I is correct but Statement II is incorrectd)Statement II is incorrect but Statement II is correctCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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