JEE Exam > JEE Questions > If f and g are two functions over real number...
Start Learning for Free
If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2 + 2, then find f-g
- a)x2+1
- b)3x + x2
- c)3x – x2-1
- d)x2+1-3x
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If f and g are two functions over real numbers defined as f(x) = 3x + ...
3x+1-(x²+2)
=3x+1-x²-2
=3x-x²-1
Hence option C is correct.
=3x+1-x²-2
=3x-x²-1
Hence option C is correct.
Free Test
FREE
| Start Free Test |
Community Answer
If f and g are two functions over real numbers defined as f(x) = 3x + ...
To find the expression for f - g, we need to subtract the given functions f(x) and g(x) from each other.
Given functions:
f(x) = 3x - 1
g(x) = x^2 - 2
To find f - g, we subtract g(x) from f(x) term by term:
f - g = (3x - 1) - (x^2 - 2)
Simplifying the expression:
f - g = 3x - 1 - x^2 + 2
Rearranging the terms:
f - g = -x^2 + 3x + 1
Therefore, the correct answer is option 'C': 3x - x^2 - 1.
Explanation:
We are given two functions, f(x) = 3x - 1 and g(x) = x^2 - 2.
To find f - g, we need to subtract g(x) from f(x).
When subtracting two functions, we subtract the corresponding terms.
Subtracting the first term:
3x - x^2
Subtracting the second term:
-1 - (-2) = -1 + 2 = 1
Combining the terms, we get:
- x^2 + 3x + 1
Therefore, the expression for f - g is -x^2 + 3x + 1.
Given functions:
f(x) = 3x - 1
g(x) = x^2 - 2
To find f - g, we subtract g(x) from f(x) term by term:
f - g = (3x - 1) - (x^2 - 2)
Simplifying the expression:
f - g = 3x - 1 - x^2 + 2
Rearranging the terms:
f - g = -x^2 + 3x + 1
Therefore, the correct answer is option 'C': 3x - x^2 - 1.
Explanation:
We are given two functions, f(x) = 3x - 1 and g(x) = x^2 - 2.
To find f - g, we need to subtract g(x) from f(x).
When subtracting two functions, we subtract the corresponding terms.
Subtracting the first term:
3x - x^2
Subtracting the second term:
-1 - (-2) = -1 + 2 = 1
Combining the terms, we get:
- x^2 + 3x + 1
Therefore, the expression for f - g is -x^2 + 3x + 1.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
Question Description
If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer?.
If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer?.
Solutions for If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If f and g are two functions over real numbers defined as f(x) = 3x + 1, g(x) = x2+ 2, then find f-ga)x2+1b)3x + x2c)3x – x2-1d)x2+1-3xCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Signup to solve all Doubts
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup