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Two closely -coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is double that of spring 'B'. The stiffness of spring 'A' will be ....... that of spring 'B'.
a)one-half
b)one- eighth
c)one-fourth
d)one-sixteenth
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Two closely -coiled helical springs 'A' and 'B' are equal in all respe...
Stiffness is inversely proportional to the no. of turns
Therefore,option d will be the correct answer.
Most Upvoted Answer
Two closely -coiled helical springs 'A' and 'B' are equal in all respe...
Answer:
The stiffness of a spring is directly proportional to the number of turns in the spring. Therefore, if the number of turns in spring A is double that of spring B, the stiffness of spring A will be four times that of spring B.
Explanation:
Stiffness of a spring is defined as the force required to produce a unit displacement in the spring. It is expressed in terms of force per unit length or force per unit displacement. The stiffness of a spring is directly proportional to the number of turns in the spring.
When a spring is compressed or stretched, the force acting on it is proportional to the displacement or compression. The spring constant, k, is defined as the force required to produce a unit displacement in the spring.
Mathematically,
k = F/x
where k is the spring constant, F is the force applied and x is the displacement produced.
Now, let's consider two closely-coiled helical springs A and B.
Given,
Number of turns in spring A = 2 x Number of turns in spring B
Let the spring constant of spring B be k.
Then, the spring constant of spring A will be
kA = 2k
This is because the stiffness of a spring is directly proportional to the number of turns in the spring.
Therefore,
kA/kB = (2k)/k = 2
kA is four times that of spring B.
Hence, the stiffness of spring A will be four times that of spring B.
Therefore, the correct option is (c) one-fourth.
The stiffness of a spring is directly proportional to the number of turns in the spring. Therefore, if the number of turns in spring A is double that of spring B, the stiffness of spring A will be four times that of spring B.
Explanation:
Stiffness of a spring is defined as the force required to produce a unit displacement in the spring. It is expressed in terms of force per unit length or force per unit displacement. The stiffness of a spring is directly proportional to the number of turns in the spring.
When a spring is compressed or stretched, the force acting on it is proportional to the displacement or compression. The spring constant, k, is defined as the force required to produce a unit displacement in the spring.
Mathematically,
k = F/x
where k is the spring constant, F is the force applied and x is the displacement produced.
Now, let's consider two closely-coiled helical springs A and B.
Given,
Number of turns in spring A = 2 x Number of turns in spring B
Let the spring constant of spring B be k.
Then, the spring constant of spring A will be
kA = 2k
This is because the stiffness of a spring is directly proportional to the number of turns in the spring.
Therefore,
kA/kB = (2k)/k = 2
kA is four times that of spring B.
Hence, the stiffness of spring A will be four times that of spring B.
Therefore, the correct option is (c) one-fourth.
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Community Answer
Two closely -coiled helical springs 'A' and 'B' are equal in all respe...
One half because stiffness is inversely proportional to the no of turn of.
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Two closely -coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is double that of spring 'B'. The stiffness of spring 'A' will be ....... that of spring 'B'. a)one-half b)one- eighth c)one-fourth d)one-sixteenthCorrect answer is option 'A'. Can you explain this answer?
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Two closely -coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is double that of spring 'B'. The stiffness of spring 'A' will be ....... that of spring 'B'. a)one-half b)one- eighth c)one-fourth d)one-sixteenthCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about Two closely -coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is double that of spring 'B'. The stiffness of spring 'A' will be ....... that of spring 'B'. a)one-half b)one- eighth c)one-fourth d)one-sixteenthCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two closely -coiled helical springs 'A' and 'B' are equal in all respects but the number of turns of spring 'A' is double that of spring 'B'. The stiffness of spring 'A' will be ....... that of spring 'B'. a)one-half b)one- eighth c)one-fourth d)one-sixteenthCorrect answer is option 'A'. Can you explain this answer?.
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