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A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct electricity, it suggests that
  • a)
    the structure of the compound involves covalent bonding only
  • b)
    the chlorine atoms must be in coordination sphere
  • c)
    the van't Hoff factor of the compound would be unity
  • d)
    on adding excess aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCI would be obtained
Correct answer is option 'B,C'. Can you explain this answer?
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Verified Answer
A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct el...
In the aqueous solution of Pd(NH3)2CI2, the atoms of chlorine I are in coordination sphere and the van't Hoff factor of the ] compound are unite.
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A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct el...
Explanation:

A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct electricity, it suggests that:

Coordination Compound:

Pd(NH3)2CI2 is a coordination compound. Coordination compounds are those compounds in which a central metal atom/ion is surrounded by a fixed number of ions or molecules in a specific geometrical arrangement. The central metal atom/ion is called the coordination centre, and the molecules or ions surrounding it are called ligands.

Covalent Bonding:

Covalent bonding is a type of chemical bonding that is characterized by the sharing of electrons between atoms. In coordination compounds, there is both covalent and ionic bonding between the central metal atom/ion and the ligands.

Conductivity:

The ability of a substance to conduct electricity depends on the presence of free ions or charged particles in the solution. If a compound does not dissociate into ions in solution, it will not conduct electricity.

Vant Hoff Factor:

The Vant Hoff factor is a measure of the extent to which a compound dissociates into ions in solution. For Pd(NH3)2CI2, the Vant Hoff factor would be unity because it does not dissociate into ions in solution.

AgNO3 Test:

When excess aqueous AgNO3 is added to a solution of Pd(NH3)2CI2, AgCI is formed by precipitation. The amount of AgCI formed can be used to determine the amount of Pd(NH3)2CI2 in the original solution.

Conclusion:

Hence, the correct options are B and C, which suggest that Pd(NH3)2CI2 is a coordination compound with covalent bonding and a Vant Hoff factor of unity, and it does not conduct electricity in solution.
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Community Answer
A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct el...
This is a coordination compound we know that coordination compounds are those which doesn't dissociate completely.it means it's vant off factor is unity so both options b ,c r correct
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Read the passage given below and answer the following questions:In ideally ionic structures, the coordination numbers of the ions are determined by electrostatic considerations. Cations surround themselves with as many anions as possible and vice versa. This maximizes the attractions between neighbouring ions of opposite charge and hence maximizes the lattice energy of the crystal. This requirement led to the formulation of the radius ratio rule for ionic structures in which the ions and the structure adopted for a particular compound depend on the relative sizes of the ions. Thus, for the stable ionic crystalline structures, there is definite radius ratio limit for a cation to fit perfectly in the lattice of anions, called radius ratio rule. This depends upon the ratio of radii of two types of ions, r+/r–.This ratio for coordination numbers 3, 4, 6 and 8 are respectively 0.155 – 0.225, 0.225 -0.414, 0.414 -0.732 and 0.732 – 1.000. The coordination number of ionic solids also depends upon temperature and pressure. On applying high pressure, coordination number increases. On the other hand, on applying high temperature, it decreases.Q.Which is not the correct statement for ionic solids in which positive and negative ions are held by strong electrostatic attractive forces?

Read the passage given below and answer the following questions:In ideally ionic structures, the coordination numbers of the ions are determined by electrostatic considerations. Cations surround themselves with as many anions as possible and vice versa. This maximizes the attractions between neighbouring ions of opposite charge and hence maximizes the lattice energy of the crystal. This requirement led to the formulation of the radius ratio rule for ionic structures in which the ions and the structure adopted for a particular compound depend on the relative sizes of the ions. Thus, for the stable ionic crystalline structures, there is definite radius ratio limit for a cation to fit perfectly in the lattice of anions, called radius ratio rule. This depends upon the ratio of radii of two types of ions, r+/r–.This ratio for coordination numbers 3, 4, 6 and 8 are respectively 0.155 – 0.225, 0.225 -0.414, 0.414 -0.732 and 0.732 – 1.000. The coordination number of ionic solids also depends upon temperature and pressure. On applying high pressure, coordination number increases. On the other hand, on applying high temperature, it decreases.Q.If the pressure of CsCl is increased, then its coordination number will

Read the passage given below and answer the following questions:In ideally ionic structures, the coordination numbers of the ions are determined by electrostatic considerations. Cations surround themselves with as many anions as possible and vice versa. This maximizes the attractions between neighbouring ions of opposite charge and hence maximizes the lattice energy of the crystal. This requirement led to the formulation of the radius ratio rule for ionic structures in which the ions and the structure adopted for a particular compound depend on the relative sizes of the ions. Thus, for the stable ionic crystalline structures, there is definite radius ratio limit for a cation to fit perfectly in the lattice of anions, called radius ratio rule. This depends upon the ratio of radii of two types of ions, r+/r–.This ratio for coordination numbers 3, 4, 6 and 8 are respectively 0.155 – 0.225, 0.225 -0.414, 0.414 -0.732 and 0.732 – 1.000. The coordination number of ionic solids also depends upon temperature and pressure. On applying high pressure, coordination number increases. On the other hand, on applying high temperature, it decreases.Q. If the radius of Nation is 95 pm and that of Cl– ion is 181 pm, the coordination number of Na+ ion is

A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct electricity, it suggests thata)the structure of the compound involves covalent bonding onlyb)the chlorine atoms must be in coordination spherec)the van't Hoff factor of the compound would be unityd)on adding excess aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCI would be obtainedCorrect answer is option 'B,C'. Can you explain this answer?
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A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct electricity, it suggests thata)the structure of the compound involves covalent bonding onlyb)the chlorine atoms must be in coordination spherec)the van't Hoff factor of the compound would be unityd)on adding excess aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCI would be obtainedCorrect answer is option 'B,C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct electricity, it suggests thata)the structure of the compound involves covalent bonding onlyb)the chlorine atoms must be in coordination spherec)the van't Hoff factor of the compound would be unityd)on adding excess aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCI would be obtainedCorrect answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A freshly prepared aqueous solution of Pd(NH3)2CI2 does not conduct electricity, it suggests thata)the structure of the compound involves covalent bonding onlyb)the chlorine atoms must be in coordination spherec)the van't Hoff factor of the compound would be unityd)on adding excess aqueous AgNO3 to 0.1 L of 0.1 M solution of the compound, 0.02 mole of AgCI would be obtainedCorrect answer is option 'B,C'. Can you explain this answer?.
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