The electric field for an em wave is: E = E0sin[(12 x 1015t – 4 ...
V(velocity/speed)= ω/wave number (K)
V= 12×1015/4×107
V=3×108 m/s
View all questions of this test
The electric field for an em wave is: E = E0sin[(12 x 1015t – 4 ...
- 2πx/λ]
where E0 is the amplitude of the electric field, t is the time, x is the position, and λ is the wavelength of the wave.
The electric field oscillates sinusoidally in both time and space, with a frequency of 12 x 10^15 Hz (or 12 petahertz). This corresponds to a wavelength of approximately 25 nanometers, which is in the ultraviolet range of the electromagnetic spectrum.
The amplitude of the electric field, E0, determines the intensity of the wave. Higher values of E0 correspond to more intense waves, while lower values correspond to weaker waves.
Overall, the electric field for an em wave provides important information about the properties and behavior of the wave, including its frequency, wavelength, and intensity.
The electric field for an em wave is: E = E0sin[(12 x 1015t – 4 ...
V(velocity/speed)= omega(w)/wave number (K)
V= 12×10^15/4×10^7
V=3×10^8 m/s