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The weight of 1 Mole of a gas of density 0.1784 g/L at NTP is? a)0.1784. b)1g. c)4g. d)4 amu?
Verified Answer
The weight of 1 Mole of a gas of density 0.1784 g/L at NTP is? a)0.178...
At NTP, 24.07 L is the volume occupied by 1 mole of a gas.
Now density = Mass / volume
So, Mass  = density x volume
                 = 0.1784 g /L x 24.07 L
               = 4.29 g.  
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Most Upvoted Answer
The weight of 1 Mole of a gas of density 0.1784 g/L at NTP is? a)0.178...
Since. One mole had 22. 4 lit. Of gas so the wt. will be 0.1784 × 23.4 = ... (3.99616 gram) = 4g..!
Community Answer
The weight of 1 Mole of a gas of density 0.1784 g/L at NTP is? a)0.178...
1 mole gas at NTP = 22.4L


MASS=DENSITY ×VOLUME
=0.1784×22.4
=3.99616
=4
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The weight of 1 Mole of a gas of density 0.1784 g/L at NTP is? a)0.1784. b)1g. c)4g. d)4 amu?
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