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A ball is dropped from a certain height such that it covers a distance of 44.1m during last second of its motion. Then calculate total height and total time of fall.?
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A ball is dropped from a certain height such that it covers a distance...
Let 'n' denote time in this case.w.k.t. S(n) = u + g/2(2n-1)44.1=0+9.8/2 (2n-1)44.1÷4.9=2n-19+1=2nn=5total time of fall=n=5.
also w.k.t.S=ut+g/2 (t^2)S=0+9.8/2 (5^2)S=4.9 (25)S=122.5mTotal height =122.5m
also w.k.t.S=ut+g/2 (t^2)S=0+9.8/2 (5^2)S=4.9 (25)S=122.5mTotal height =122.5m
Community Answer
A ball is dropped from a certain height such that it covers a distance...
Calculating Total Height and Total Time of Fall
Given:
- Distance covered in the last second = 44.1m
Calculating Total Height:
- The distance covered in the last second of motion is the sum of the distance traveled in the last second before coming to rest.
- Using the formula for distance covered in the last second: \( s = u + (v - u) \times t \), where:
- \( s = 44.1m \) (distance covered in the last second)
- \( u = 0 \) (initial velocity)
- \( v = 0 \) (final velocity)
- \( t = 1s \) (time taken in the last second)
- Substituting the values, we get: \( 44.1 = 0 + (0 - 0) \times 1 \)
- Therefore, the total height of the drop = 44.1m
Calculating Total Time of Fall:
- To calculate the total time of fall, we need to consider the time taken for the ball to cover the total height.
- Using the equation of motion: \( s = ut + \frac{1}{2}at^2 \), where:
- \( s = 44.1m \) (total height)
- \( u = 0 \) (initial velocity)
- \( a = 9.81ms^{-2} \) (acceleration due to gravity)
- \( t \) is the total time of fall
- Substituting the values, we get: \( 44.1 = 0 + \frac{1}{2} \times 9.81 \times t^2 \)
- Solving for \( t \), we find: \( t = \sqrt{\frac{2 \times 44.1}{9.81}} \approx 3s \)
- Therefore, the total time of fall = 3 seconds
In conclusion, the total height of the drop is 44.1m and the total time of fall is 3 seconds.
Given:
- Distance covered in the last second = 44.1m
Calculating Total Height:
- The distance covered in the last second of motion is the sum of the distance traveled in the last second before coming to rest.
- Using the formula for distance covered in the last second: \( s = u + (v - u) \times t \), where:
- \( s = 44.1m \) (distance covered in the last second)
- \( u = 0 \) (initial velocity)
- \( v = 0 \) (final velocity)
- \( t = 1s \) (time taken in the last second)
- Substituting the values, we get: \( 44.1 = 0 + (0 - 0) \times 1 \)
- Therefore, the total height of the drop = 44.1m
Calculating Total Time of Fall:
- To calculate the total time of fall, we need to consider the time taken for the ball to cover the total height.
- Using the equation of motion: \( s = ut + \frac{1}{2}at^2 \), where:
- \( s = 44.1m \) (total height)
- \( u = 0 \) (initial velocity)
- \( a = 9.81ms^{-2} \) (acceleration due to gravity)
- \( t \) is the total time of fall
- Substituting the values, we get: \( 44.1 = 0 + \frac{1}{2} \times 9.81 \times t^2 \)
- Solving for \( t \), we find: \( t = \sqrt{\frac{2 \times 44.1}{9.81}} \approx 3s \)
- Therefore, the total time of fall = 3 seconds
In conclusion, the total height of the drop is 44.1m and the total time of fall is 3 seconds.
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A ball is dropped from a certain height such that it covers a distance of 44.1m during last second of its motion. Then calculate total height and total time of fall.?
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A ball is dropped from a certain height such that it covers a distance of 44.1m during last second of its motion. Then calculate total height and total time of fall.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A ball is dropped from a certain height such that it covers a distance of 44.1m during last second of its motion. Then calculate total height and total time of fall.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is dropped from a certain height such that it covers a distance of 44.1m during last second of its motion. Then calculate total height and total time of fall.?.
A ball is dropped from a certain height such that it covers a distance of 44.1m during last second of its motion. Then calculate total height and total time of fall.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A ball is dropped from a certain height such that it covers a distance of 44.1m during last second of its motion. Then calculate total height and total time of fall.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ball is dropped from a certain height such that it covers a distance of 44.1m during last second of its motion. Then calculate total height and total time of fall.?.
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