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The last term of the series 5, 7, 9,….. to 21 terms is
  • a)
    44
  • b)
    43
  • c)
    45
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The last term of the series 5, 7, 9,….. to 21 terms isa)44b)43c)...
It is a series of odd number without first two entries 1 and 3

general term for odd is (2n - 1) where n >= 1

Series goes like this for odd

(2n - 1), (2n-1+2), (2n-1+2+2),………

(2n-1), (2n+1),(2n+3),…..

But

1 and 3 is not in series so (2n-1) (2n+1) is not taken

So next is (2n + 3)

then general patter here is (2n + 3) where n >= 1

n = 1 then 2X1 + 3 = 5

n = 2 then 2X2 + 3 = 7

For

n = 21

Ans = 2 X 21 +3

= 45
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Most Upvoted Answer
The last term of the series 5, 7, 9,….. to 21 terms isa)44b)43c)...
Given series: 5, 7, 9, ..., to 21 terms.

To find: The last term of the series.

Approach:

- We can observe that the series is an arithmetic progression (AP) with a common difference of 2.
- The nth term of an AP is given by the formula: a + (n-1)d, where 'a' is the first term and 'd' is the common difference.

Using the above formula, we can find the last term of the given series as follows:

- First term, a = 5
- Common difference, d = 2
- Number of terms, n = 21 (given)

Substituting the values in the formula, we get:

- Last term, Tn = a + (n-1)d
- T21 = 5 + (21-1)2 = 5 + 40 = 45

Therefore, the last term of the given series is 45.

Hence, the correct option is (c) 45.
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The last term of the series 5, 7, 9,….. to 21 terms isa)44b)43c)...
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The last term of the series 5, 7, 9,….. to 21 terms isa)44b)43c)45d)none of theseCorrect answer is option 'C'. Can you explain this answer?
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