A 3micro farad is charged to a pot. of 300V & 2 micro farad capacitor ...
When plates of opposite polarity are joined together, then 1st capacitor having higher amount of charge will first neutralise the whole charge on the 2nd capacitor. And then the remaining charge is shared to bring C1 and C2 to same potential, i.e, finally the capacitors are parallel.for 1st capacitor C1 = 3 microfarad, V1 = 300 Voltcharge Q1 = 3×300 = 900 micro-coulombfor 2nd one, C1 = 2 microfarad, V1 = 200 Voltcharge Q2 = 2×200 = - 400 micro-coulomb[-ve sign, because it is having opposite polarity]Common potential after connection,V' = (Q1+Q2)÷(C1+C2)= (900-400)÷(3+2)= 100 VoltHence,new charge on 1st capacitor,Q1' = C1×V' = (3×100) = 300 micro-coulombCharge transferred =Q1 - Q1' = (900-300) = 600 micro-coulomb[That's the answer]New charge on 2nd capacitor =Q2' = C2×V' = (2×100) = 200 micro-coulombThis shows that after joining the plates of opposite polarity, 600 Micro-coulomb charge flows from C1 to C2, of which 400 micro-coulomb is neutralised due to -ve charge on C2Hope this helps. Ask me if you have any doubts.
A 3micro farad is charged to a pot. of 300V & 2 micro farad capacitor ...
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