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JEE Exam  >  JEE Questions  >  8Cr=8Cp. Soa)r = p or r = 8pb)r = p or r + p ... Start Learning for Free
8Cr = 8Cp. So
  • a)
    r = p or r = 8p
  • b)
    r = p or r + p = 8
  • c)
    r = p or r – p = 8
  • d)
    r = p or r = 2p
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
8Cr=8Cp. Soa)r = p or r = 8pb)r = p or r + p = 8c)r = p or r – p...
8Cr = 8Cp = 8C8-p     
So, either r = p or r = 8 – p
i.e. r = p or r + p = 8
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Most Upvoted Answer
8Cr=8Cp. Soa)r = p or r = 8pb)r = p or r + p = 8c)r = p or r – p...
8Cr = 8Cp = 8C8-p     
So, either r = p or r = 8 – p
i.e. r = p or r + p = 8 
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Community Answer
8Cr=8Cp. Soa)r = p or r = 8pb)r = p or r + p = 8c)r = p or r – p...
8Cr = 8Cp = 8C8-p     
So, either r = p or r = 8 – p
i.e. r = p or r + p = 8
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A gaseous sample is generally allowed to do only expansion/compression type of work against its surroundings. The work done in case of an irreversible expansion (in the intermediate stages, of expansion/compression the states of gases are not define d). The work done can be calculated usingdW = NextdVwhile in case of reversible process the work done can be calculated using dw = PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process.Since d w = P d V so magnitude of worked one can also be calculated by, calculating the area under the PV curve of the reversible process in PV diagram.Q.If four identical samples of an ideal gas initially at similar state (P0, Vo, T0) are allowed to expand to double their volumes by four different processes..I : by isothermal irreversible process II : by reversible process having equation P2V = constant III : by reversible adiabatic process IV: by irreversible adiabatic expansion against constant external pressure.Then in the graph shown the final state is represented by four different points then, the correct match can be

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8Cr=8Cp. Soa)r = p or r = 8pb)r = p or r + p = 8c)r = p or r – p = 8d)r = p or r = 2pCorrect answer is option 'B'. Can you explain this answer?
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